Math Problem Statement

Prove that √2 is an irrational number

Solution

To prove that 2\sqrt{2} is irrational, we use a classical proof by contradiction.

Steps of the proof:

  1. Assume the opposite: Suppose 2\sqrt{2} is a rational number. By definition, a rational number can be expressed as a fraction of two integers pq\frac{p}{q}, where pp and qq are integers, q0q \neq 0, and the fraction is in its lowest terms (i.e., pp and qq have no common factors other than 1, they are coprime).

    So, let's assume: 2=pq\sqrt{2} = \frac{p}{q} Squaring both sides, we get: 2=p2q22 = \frac{p^2}{q^2} This implies: p2=2q2p^2 = 2q^2

  2. Examine the implications: From p2=2q2p^2 = 2q^2, we see that p2p^2 is an even number because it equals 2q22q^2 (which is obviously even). If p2p^2 is even, then pp itself must also be even (because the square of an odd number is odd). So, let p=2kp = 2k for some integer kk.

  3. Substitute and simplify: Now, substitute p=2kp = 2k into the equation p2=2q2p^2 = 2q^2: (2k)2=2q2(2k)^2 = 2q^2 This simplifies to: 4k2=2q24k^2 = 2q^2 Dividing both sides by 2, we get: 2k2=q22k^2 = q^2 This implies that q2q^2 is also even, which means qq must be even as well.

  4. Contradiction: If both pp and qq are even, then they have a common factor of 2. But this contradicts our original assumption that pp and qq are coprime (they should not have any common factors other than 1).

Conclusion:

Since our assumption that 2\sqrt{2} is rational leads to a contradiction, it follows that 2\sqrt{2} must be irrational.


Would you like more details on any step or have any other questions?

Here are 5 related questions to expand your understanding:

  1. What is the definition of an irrational number?
  2. Can the same method be used to prove that 3\sqrt{3} is irrational?
  3. Why is it necessary for the numbers pp and qq to be coprime?
  4. How does this proof relate to the Fundamental Theorem of Arithmetic?
  5. Can the method of contradiction be used for other types of mathematical proofs?

Tip: In proofs by contradiction, it's important to assume the exact opposite of what you're trying to prove and carefully follow the logical implications of that assumption until a contradiction arises.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Rational and Irrational Numbers
Proof by Contradiction

Formulas

√2 = p/q
p² = 2q²
p = 2k
q² = 2k²

Theorems

Fundamental Theorem of Arithmetic
Properties of Rational Numbers

Suitable Grade Level

Grades 10-12