Math Problem Statement

Prove that √2 is irrational by contradiction

Solution

To prove that 2\sqrt{2} is irrational by contradiction, follow these steps:

Assumption for Contradiction

Assume that 2\sqrt{2} is rational. By definition, a rational number can be expressed as a fraction pq\frac{p}{q}, where pp and qq are integers, q0q \neq 0, and the fraction is in simplest form (i.e., gcd(p,q)=1\gcd(p, q) = 1).

Thus: 2=pq.\sqrt{2} = \frac{p}{q}.

Step 1: Square Both Sides

Squaring both sides of the equation: 2=p2q2.2 = \frac{p^2}{q^2}.

Multiply through by q2q^2 to eliminate the fraction: p2=2q2.p^2 = 2q^2.

Step 2: Implication About p2p^2

Since p2=2q2p^2 = 2q^2, this shows that p2p^2 is even (because it is two times an integer, 2q22q^2).

Step 3: Implication About pp

If p2p^2 is even, then pp must also be even (because the square of an odd number is odd). Therefore, we can write p=2kp = 2k, where kk is an integer.

Step 4: Substitute p=2kp = 2k Into the Equation

Substitute p=2kp = 2k into the equation p2=2q2p^2 = 2q^2: (2k)2=2q2.(2k)^2 = 2q^2.

Simplify: 4k2=2q2.4k^2 = 2q^2.

Divide through by 2: 2k2=q2.2k^2 = q^2.

Step 5: Implication About q2q^2

This shows that q2q^2 is also even. If q2q^2 is even, then qq must also be even.

Step 6: Contradiction

If both pp and qq are even, then they have a common factor of 2. This contradicts the assumption that pq\frac{p}{q} is in simplest form (gcd(p,q)=1\gcd(p, q) = 1).

Conclusion

The assumption that 2\sqrt{2} is rational leads to a contradiction. Therefore, 2\sqrt{2} is irrational.


Would you like further clarification or examples of similar proofs?

Related Questions

  1. Can this proof be generalized for n\sqrt{n}, where nn is not a perfect square?
  2. How can you use a similar proof to show that 3\sqrt{3} is irrational?
  3. What are the properties of rational and irrational numbers that make this proof valid?
  4. Can you explain the importance of the assumption that gcd(p,q)=1\gcd(p, q) = 1?
  5. How does this proof demonstrate the power of proof by contradiction?

Tip

When proving irrationality, always verify that the initial assumption of the number being rational is well-defined, ensuring no logical inconsistencies in the argument.

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Math Problem Analysis

Mathematical Concepts

Irrational Numbers
Proof by Contradiction
Properties of Integers

Formulas

√2 = p/q, where p and q are integers with gcd(p, q) = 1
p^2 = 2q^2

Theorems

Fundamental Theorem of Arithmetic
Properties of Rational and Irrational Numbers

Suitable Grade Level

Grades 9-12