Math Problem Statement

In context of discrete math prove that the square root of 2 is irrational number

Solution

To prove that 2\sqrt{2} is irrational, we will proceed by contradiction. That is, we will assume that 2\sqrt{2} is rational and show that this assumption leads to a contradiction.


Proof by Contradiction:

  1. Assumption:
    Assume 2\sqrt{2} is rational. This means that it can be written as a fraction of two integers: 2=pq\sqrt{2} = \frac{p}{q} where pp and qq are integers with no common factors (i.e., the fraction pq\frac{p}{q} is in its simplest form). Also, q0q \neq 0.

  2. Square both sides:
    2=p2q22 = \frac{p^2}{q^2} Multiply both sides by q2q^2 to get: 2q2=p22q^2 = p^2 This shows that p2p^2 is even, since it is equal to 2q22q^2.

  3. Implication that pp is even:
    Since p2p^2 is even, pp must also be even. (If pp were odd, then p2p^2 would be odd as well, which contradicts our result.)
    So, let p=2kp = 2k for some integer kk.

  4. Substitute p=2kp = 2k into the equation 2q2=p22q^2 = p^2:
    2q2=(2k)2=4k22q^2 = (2k)^2 = 4k^2 Divide both sides by 2: q2=2k2q^2 = 2k^2 This shows that q2q^2 is also even, which means that qq must be even as well.

  5. Contradiction:
    Since both pp and qq are even, they have a common factor of 2. This contradicts our assumption that pq\frac{p}{q} is in its simplest form (i.e., that pp and qq have no common factors).


Conclusion:

Since our assumption that 2\sqrt{2} is rational leads to a contradiction, the original assumption must be false. Therefore, 2\sqrt{2} is irrational.


Would you like a deeper breakdown of any part of the proof?


Here are 5 related questions for further exploration:

  1. How can this proof method be generalized for n\sqrt{n}, where nn is not a perfect square?
  2. What is the definition of an irrational number, and how does it differ from a rational number?
  3. Can similar proofs show that 3\sqrt{3} or 5\sqrt{5} are irrational?
  4. What is the connection between irrational numbers and real numbers?
  5. How does this proof relate to the fundamental theorem of arithmetic?

Tip: Proofs by contradiction are powerful tools in mathematics, especially when dealing with irrational numbers and other properties that seem counterintuitive at first.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Irrational Numbers
Proof by Contradiction

Formulas

Assume \(\sqrt{2} = \frac{p}{q}\) and derive contradictions

Theorems

Fundamental Theorem of Arithmetic
Properties of Rational and Irrational Numbers

Suitable Grade Level

Grades 10-12