Math Problem Statement

Montrer que (a, b ∈ ℝ) : a² + b² = 1 ⇒ |a + b| ≤ √2

Solution

The question shown in the image is:

"2. Montrer que (a, b ∈ ℝ) : a² + b² = 1 ⇒ |a + b| ≤ √2"

This is a mathematical proof request. The statement is saying that for any real numbers aa and bb such that a2+b2=1a^2 + b^2 = 1 (which represents a point on the unit circle), we need to show that the absolute value of their sum a+b|a + b| is less than or equal to 2\sqrt{2}.

Solution Outline:

We begin by interpreting the condition a2+b2=1a^2 + b^2 = 1. This is the equation of a unit circle in the plane. Our goal is to demonstrate that the maximum value of a+b|a + b| when aa and bb satisfy this equation does not exceed 2\sqrt{2}.

  1. Rewrite the expression a+b2|a + b|^2: a+b2=(a+b)2=a2+2ab+b2|a + b|^2 = (a + b)^2 = a^2 + 2ab + b^2 From a2+b2=1a^2 + b^2 = 1, we substitute: a+b2=1+2ab|a + b|^2 = 1 + 2ab

  2. Find bounds for 2ab2ab: Since a2+b2=1a^2 + b^2 = 1, both aa and bb lie on the unit circle, and the product abab can be maximized or minimized depending on the angle between the two points.

    Using the trigonometric parametrization of the unit circle: a=cos(θ),b=sin(θ)a = \cos(\theta), \quad b = \sin(\theta) Then: ab=cos(θ)sin(θ)=12sin(2θ)ab = \cos(\theta)\sin(\theta) = \frac{1}{2} \sin(2\theta) So, 2ab=sin(2θ)2ab = \sin(2\theta), and the maximum value of sin(2θ)\sin(2\theta) is 1 and the minimum is -1. Therefore: 12ab1-1 \leq 2ab \leq 1

  3. Find bounds for a+b2|a + b|^2: Since a+b2=1+2ab|a + b|^2 = 1 + 2ab, we substitute the bounds for 2ab2ab: 11a+b21+11 - 1 \leq |a + b|^2 \leq 1 + 1 0a+b220 \leq |a + b|^2 \leq 2

  4. Conclude: Taking the square root of both sides: 0a+b20 \leq |a + b| \leq \sqrt{2} Hence, we have shown that a+b2|a + b| \leq \sqrt{2}, as required.


Would you like further clarification on any of the steps? Here are five related questions to consider:

  1. How can the Cauchy-Schwarz inequality be used to derive similar bounds?
  2. What are the geometric implications of this inequality on the unit circle?
  3. Can this result be extended to higher dimensions, for example, with three variables?
  4. What is the maximum value of a+b|a + b| when aa and bb are real numbers not restricted to the unit circle?
  5. How does the parametrization a=cos(θ)a = \cos(\theta) and b=sin(θ)b = \sin(\theta) relate to other trigonometric identities?

Tip: When working with inequalities on the unit circle, parametrization using trigonometric functions can simplify the analysis.

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Math Problem Analysis

Mathematical Concepts

Inequalities
Geometry
Trigonometry

Formulas

a² + b² = 1 (Equation of the unit circle)
|a + b|² = a² + 2ab + b²

Theorems

Cauchy-Schwarz Inequality
Trigonometric Parametrization

Suitable Grade Level

Grades 10-12