Given the data:
Was married = 40%
Not yet married = 60%
If two people are selected, what is the probability that the first one was not married while the second was married?
Select one:

a.
24%

b.
10%

c.
100%

d.
36%

To solve this problem, we need to calculate the probability that the first person selected is "not yet married" and the second person is "married."

Given:
- Probability that a person is "not yet married" = 60% = 0.6
- Probability that a person is "married" = 40% = 0.4

The probability that the first person is "not yet married" and the second is "married" is the product of the individual probabilities:

\[
\text{Probability} = \text{P(not yet married)} \times \text{P(married)} = 0.6 \times 0.4 = 0.24
\]

Thus, the probability is 24%, which corresponds to option **a**.

**Answer:** **a. 24%**

Do you need more details or have any questions? Here are 8 related questions to explore further:
1. What is the probability that both selected individuals are not married?
2. What is the probability that both selected individuals are married?
3. If three people are selected, what is the probability that all are married?
4. What is the probability that the first person is married and the second is not?
5. How would the probability change if 50% were married and 50% were not?
6. How can conditional probability be used in this scenario?
7. What if we select three people; what is the probability of the sequence "married, not married, married"?
8. How does this type of probability relate to real-life demographic studies?

**Tip:** Always multiply the probabilities of independent events to find the overall probability of a specific sequence of outcomes.

Calculate the probability of selecting a person who is not yet married first and a person who is married second. Understand how to apply probability calculations with given percentages. Suitable for Grades 9-12.

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