To solve this problem, we need to calculate the probability that the first person selected is "married" and the second person is "not yet married."

Given:

• Probability that a person is "married" = 40% = 0.4
• Probability that a person is "not yet married" = 60% = 0.6

The probability that the first person is "married" and the second is "not yet married" is the product of the individual probabilities:

$\text{Probability} = \text{P(married)} \times \text{P(not yet married)} = 0.4 \times 0.6 = 0.24$

Thus, the probability is 24%, which corresponds to option c.

Answer: c. 24%

Do you need more details or have any questions? Here are 8 related questions to explore further:

1. What is the probability that the first person is not married and the second one is also not married?
2. What is the probability that the first person is married and the second one is also married?
3. If two people are selected, what is the probability that one of them is married?
4. How does the sequence of selection (first or second) affect the probabilities?
5. What if the probabilities were reversed (60% married, 40% not married)?
6. How would the probability change if three people were selected?
7. What is the probability that exactly one person out of two is married?
8. How do these types of problems relate to concepts like independence and conditional probability?

Tip: When dealing with independent events, always multiply the