Math Problem Statement

Events A and B are mutually exclusive. Suppose event A occurs with probability 0.2 and event B occurs with probability 0.39. Compute the following. (a)Compute the probability that A occurs or B does not occur (or both). (b)Compute the probability that either A occurs without B occurring or B occurs without A occurring.

Solution

Let's break down the problem into the two parts you're asked to compute:

Part (a): Compute the probability that A occurs or B does not occur (or both).

This can be written as P(ABc)P(A \cup B^c).

Solution:

To compute P(ABc)P(A \cup B^c), we can use the following identity: P(ABc)=P(A)+P(Bc)P(ABc)P(A \cup B^c) = P(A) + P(B^c) - P(A \cap B^c) However, since AA and BB are mutually exclusive, AB=A \cap B = \emptyset, which means P(AB)=0P(A \cap B) = 0. This also implies that ABc=AA \cap B^c = A.

So, P(ABc)=P(A)P(A \cap B^c) = P(A).

Now, calculate: P(Bc)=1P(B)=10.39=0.61P(B^c) = 1 - P(B) = 1 - 0.39 = 0.61

Substitute the values: P(ABc)=P(A)+P(Bc)P(ABc)=0.2+0.610.2=0.61P(A \cup B^c) = P(A) + P(B^c) - P(A \cap B^c) = 0.2 + 0.61 - 0.2 = 0.61

Thus, the probability that AA occurs or BB does not occur (or both) is 0.61.

Part (b): Compute the probability that either A occurs without B occurring or B occurs without A occurring.

This can be interpreted as the probability of AA occurring while BB does not, or BB occurring while AA does not. This can be written as P(ABc)+P(BAc)P(A \cap B^c) + P(B \cap A^c).

Solution:

Since AA and BB are mutually exclusive: P(A \cap B^c) = P(A) \quad \text{(since A \cap B = \emptyset)} P(B \cap A^c) = P(B) \quad \text{(since B \cap A = \emptyset)}

Thus, we add these probabilities: P(ABc)+P(BAc)=P(A)+P(B)=0.2+0.39=0.59P(A \cap B^c) + P(B \cap A^c) = P(A) + P(B) = 0.2 + 0.39 = 0.59

So, the probability that either AA occurs without BB occurring or BB occurs without AA occurring is 0.59.

Summary:

  • (a) The probability that AA occurs or BB does not occur (or both) is 0.61.
  • (b) The probability that either AA occurs without BB occurring or BB occurs without AA occurring is 0.59.

Would you like further details on these computations, or do you have any questions?

Here are some related questions you might explore:

  1. What is the probability that neither A nor B occurs?
  2. If A and B were not mutually exclusive, how would the calculations change?
  3. What is the probability that both A and B occur?
  4. What is the probability that either A or B occurs?
  5. How would these probabilities change if the events were independent?
  6. What is the significance of events being mutually exclusive in probability theory?
  7. How do you compute conditional probabilities for mutually exclusive events?
  8. How would the situation change if additional events C and D were introduced?

Tip: When dealing with mutually exclusive events, always remember that the probability of both events occurring simultaneously is zero.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Mutually Exclusive Events
Union of Events
Complement of Events

Formulas

Probability of Union: P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
Complement Rule: P(B^c) = 1 - P(B)

Theorems

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Suitable Grade Level

High School