Math Problem Statement

What is the probability of getting a queue number that is an even number or a multiple of 3 in the range 1 to 20, and what is the probability that a randomly selected student from a group of 100 participates in basketball or futsal extracurricular activities?

Solution

From the image, there are two mathematical problems visible. Let's focus on each:

Problem 3:

The question asks about the probability of getting a queue number that is an even number or a multiple of 3. The queue numbers range from 1 to 20.

We need to find the number of favorable outcomes where the queue number is either:

  1. An even number (2, 4, 6, 8, 10, 12, 14, 16, 18, 20).
  2. A multiple of 3 (3, 6, 9, 12, 15, 18).

Notice that the numbers 6, 12, and 18 are both even and multiples of 3, so we don't double-count these.

  • Even numbers: 10 numbers (2, 4, 6, 8, 10, 12, 14, 16, 18, 20)
  • Multiples of 3: 6 numbers (3, 6, 9, 12, 15, 18)
  • Common numbers (multiples of 3 and even): 3 numbers (6, 12, 18)

Using the inclusion-exclusion principle, the total favorable outcomes are: 10+63=1310 + 6 - 3 = 13

The probability is the number of favorable outcomes over the total number of outcomes (which is 20): Probability=1320\text{Probability} = \frac{13}{20} Thus, the answer is C. 1320\frac{13}{20}.


Problem 4:

This problem involves probability regarding extracurricular activities. We are given that out of 100 students:

  • 60 students participate in basketball extracurricular activities.
  • 50 students participate in futsal extracurricular activities.
  • There are 10 students who participate in both.

We need to find the probability that a randomly selected student from these 100 students participates in either basketball or futsal.

Using the inclusion-exclusion principle:

  • Total students involved in either activity is: 60+5010=10060 + 50 - 10 = 100 This means that 100 students are involved in at least one activity, so the probability of selecting one involved in either is: Probability=100100=1\text{Probability} = \frac{100}{100} = 1 Thus, the answer is A. 60%.

Would you like to dive deeper into any of the concepts or have further questions?

Here are 5 related questions for more practice:

  1. What is the probability of getting a number that is both a multiple of 5 and an even number in a range from 1 to 30?
  2. How would the probability change if there were 200 students and only 80 participated in basketball?
  3. Can the inclusion-exclusion principle be applied to three sets? If so, how?
  4. What if there were 12 students involved in both activities, how would the answer in problem 4 change?
  5. What is the probability of getting an odd number that is not a multiple of 3 between 1 and 20?

Tip: When solving probability problems, always check for overlaps (common elements) between the sets to avoid double-counting!

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Math Problem Analysis

Mathematical Concepts

Probability
Inclusion-Exclusion Principle

Formulas

Probability = Number of favorable outcomes / Total number of outcomes
Inclusion-Exclusion Principle: |A ∪ B| = |A| + |B| - |A ∩ B|

Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 9-11