Eight cards with one letter on each card spell out the word SURPRISE. If you choose one card at random, what is the probability of this event?


To solve this problem, we first identify the total number of cards and the letters on them.

The word "SURPRISE" has 8 letters, which means there are 8 cards in total.

Now, let's consider the probability of choosing any one specific card from these 8 cards. The probability of randomly choosing a particular card (any one of the 8 letters) is given by the formula for probability:

\[
P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
\]

Since there is only 1 favorable outcome (choosing one specific card), the probability is:

\[
P(\text{choosing one card}) = \frac{1}{8}
\]

Thus, the probability of choosing any one card from the 8 cards is \( \frac{1}{8} \).

Would you like more details, or do you have any questions?

Here are 5 related questions to deepen your understanding:
1. What is the probability of choosing the letter 'S' from the word SURPRISE?
2. If you draw two cards without replacement, what is the probability of choosing 'S' first and 'U' second?
3. What is the probability of not drawing the letter 'P'?
4. How does the probability change if you choose two cards with replacement?
5. What is the probability of selecting a vowel (U, I, or E) from the cards?

**Tip:** In probability, always verify whether you're drawing with or without replacement, as it affects the total number of outcomes.

Eight cards with one letter on each card spell out the word SURPRISE. If you choose one card at random, what is the probability of this event?

Find out how to calculate the probability of drawing one card at random from eight cards spelling the word SURPRISE. This problem demonstrates the application of basic probability principles and is suitable for students in Grades 5-7.

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