To solve this problem, we need to calculate the probability that at least one of the seven babies is a boy. The complementary event is that all seven babies are girls.

The given probability of a baby being a girl is 0.462, so the probability of a baby being a boy is:

$P(\text{boy}) = 1 - 0.462 = 0.538$

Step 1: Find the probability that all seven babies are girls.

The probability of all seven babies being girls is:

$P(\text{all girls}) = (0.462)^7$

Step 2: Use the complement rule.

The probability of at least one boy is the complement of the probability of all seven babies being girls:

$P(\text{at least one boy}) = 1 - P(\text{all girls}) = 1 - (0.462)^7$

Now, let's calculate this value.

$P(\text{all girls}) = (0.462)^7 = 0.00106$

$P(\text{at least one boy}) = 1 - 0.00106 = 0.99894$

Thus, the probability that at least one of the seven babies is a boy is approximately:

$\boxed{0.999}$

(Rounded to three decimal places)

Would you like any further details or clarifications?

Here are 5 questions related to this topic:

1. What is the probability that all seven babies are boys?
2. How does the binomial distribution apply to problems like this?
3. What if we were looking for exactly 3 boys in 7 births? How would you calculate that?
4. How would the answer change if the probability of a girl was 0.5 instead of 0.462?
5. How can the complement rule simplify probability calculations?

Tip: When calculating "at least one" probabilities, it's often easier to use the complement rule and calculate the probability of the opposite event.