To find the probability that at least one of the seven randomly selected births is a girl, we can use the concept of complementary probability.

Steps to Solve:

1. Calculate the probability of a single event:
   The probability that a baby is a boy is $P(\text{Boy}) = 0.529$.
   Therefore, the probability that a baby is a girl is $P(\text{Girl}) = 1 - 0.529 = 0.471$.

2. Find the probability of all events being boys:
   The probability that all seven babies are boys is $P(\text{All Boys}) = 0.529^7$.

3. Use the complementary probability:
   The probability that at least one of the seven babies is a girl is the complement of all seven babies being boys. $P(\text{At least one girl}) = 1 - P(\text{All Boys})$

Calculation:

$P(\text{All Boys}) = 0.529^7 \approx 0.0383$ $P(\text{At least one girl}) = 1 - 0.0383 \approx 0.9617$

Thus, the probability that at least one of the seven randomly selected births is a girl is approximately 0.9617.

Would you like any more details or have any questions?

Related Questions:

1. What is the probability that all seven babies are girls?
2. How does the probability change if the number of births increases to 10?
3. What is the probability that exactly four out of the seven babies are girls?
4. How would you calculate the expected number of girls in seven births?
5. What is the variance of the number of girls in seven births?

Tip: Complementary probability is a powerful technique to simplify problems, especially when calculating the probability of "at least one" event.