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We are working with a standard deck of 52 cards, and we need to calculate:

### Part (a) The probability of drawing an ace or a queen.
1. In a standard deck, there are 4 aces (one for each suit: hearts, diamonds, clubs, and spades) and 4 queens (one for each suit).
2. Therefore, the total number of favorable outcomes (aces or queens) is:
   \[
   4 \text{ (aces)} + 4 \text{ (queens)} = 8 \text{ favorable outcomes}.
   \]
3. The total number of possible outcomes in the experiment (drawing any card) is 52 (since there are 52 cards in the deck).

Thus, the probability \( P \) of drawing an ace or a queen is:
\[
P(\text{ace or queen}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{8}{52} = \frac{2}{13}.
\]

So, the probability is \( \frac{2}{13} \).

Would you like details for part (b) or explanations on the concept of odds?

### Related questions:
1. How do we calculate the odds in favor of drawing an ace or a queen?
2. What are the odds against drawing an ace or a queen?
3. How does the probability of a card being a face card (jack, queen, or king) compare to the probability of drawing an ace?
4. What is the probability of drawing either a heart or a spade from a standard deck of cards?
5. How do we calculate the probability of drawing two aces consecutively without replacement?

### Tip:
In probability problems involving cards, always identify the total number of favorable outcomes and the total possible outcomes. Simplifying fractions helps make probabilities easier to compare and understand.

For the experiment of drawing a single card from a standard 52-card deck, find (a) the probability of drawing an ace or queen.

Learn how to calculate the probability of drawing an ace or queen from a standard 52-card deck. This solution covers the basics of probability and combinatorics, suitable for students in Grades 7-9.

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