Math Problem Statement
Solution
The problem is to evaluate the indefinite integral
as a power series, and then determine the radius and interval of convergence.
Step 1: Represent as a power series
The Taylor series expansion for around is:
So, the logarithm function expands to:
Step 2: Integrate term by term
Now, integrate the series term by term:
Integrating each term:
Thus, the power series for the integral is:
or equivalently:
where is the constant of integration.
Step 3: Radius and Interval of Convergence
The series representation of converges for , so the power series for the integral also converges within this interval. At the endpoints ():
- For , the series diverges (harmonic series test).
- For , the series alternates but does not converge absolutely.
Thus, the radius of convergence is , and the interval of convergence is:
Final Answer:
- Power series for the integral:
-
Radius of convergence: .
-
Interval of convergence: .
Would you like further details or examples? Here are some related questions for exploration:
- What is the Taylor expansion for , and how does it differ?
- How would the result change if we integrated instead?
- Can we express the series in terms of definite integrals, such as ?
- What happens if you shift the center of the power series (e.g., expand around )?
- How can you verify convergence at the boundary points more rigorously?
Tip: When integrating series term by term, always verify the radius of convergence after integration!
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Calculus
Power Series
Integration
Convergence of Series
Formulas
ln(1+x) = ∑_{n=1}^∞ (-1)^{n+1} (x^n / n), |x| < 1
∫ x^n dx = x^{n+1} / (n+1)
Theorems
Taylor Series Expansion for ln(1+x)
Radius and Interval of Convergence
Suitable Grade Level
Undergraduate Mathematics