Math Problem Statement

Evaluate the indefinite integral ∫ ln(1 + x) dx as a power series. Then find the radius and interval of convergence.

Solution

The problem is to evaluate the indefinite integral

ln(1+x)dx\int \ln(1+x) \, dx

as a power series, and then determine the radius and interval of convergence.


Step 1: Represent ln(1+x)\ln(1+x) as a power series

The Taylor series expansion for ln(1+x)\ln(1+x) around x=0x = 0 is:

ln(1+x)=n=1(1)n+1xnn,x<1.\ln(1+x) = \sum_{n=1}^\infty (-1)^{n+1} \frac{x^n}{n}, \quad |x| < 1.

So, the logarithm function expands to:

ln(1+x)=xx22+x33x44+\ln(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \dots


Step 2: Integrate term by term

Now, integrate the series term by term:

ln(1+x)dx=(xx22+x33x44+)dx.\int \ln(1+x) \, dx = \int \left( x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \dots \right) dx.

Integrating each term:

xdx=x22,x22dx=x36,x33dx=x412,\int x \, dx = \frac{x^2}{2}, \quad \int \frac{x^2}{2} \, dx = \frac{x^3}{6}, \quad \int \frac{x^3}{3} \, dx = \frac{x^4}{12}, \dots

Thus, the power series for the integral is:

ln(1+x)dx=x22x36+x412x520++C,\int \ln(1+x) \, dx = \frac{x^2}{2} - \frac{x^3}{6} + \frac{x^4}{12} - \frac{x^5}{20} + \dots + C,

or equivalently:

ln(1+x)dx=n=1(1)n+1xn+1n(n+1)+C,\int \ln(1+x) \, dx = \sum_{n=1}^\infty (-1)^{n+1} \frac{x^{n+1}}{n(n+1)} + C,

where CC is the constant of integration.


Step 3: Radius and Interval of Convergence

The series representation of ln(1+x)\ln(1+x) converges for x<1|x| < 1, so the power series for the integral also converges within this interval. At the endpoints (x=±1x = \pm 1):

  • For x=1x = 1, the series diverges (harmonic series test).
  • For x=1x = -1, the series alternates but does not converge absolutely.

Thus, the radius of convergence is R=1R = 1, and the interval of convergence is:

(1,1).(-1, 1).


Final Answer:

  1. Power series for the integral:

ln(1+x)dx=n=1(1)n+1xn+1n(n+1)+C.\int \ln(1+x) \, dx = \sum_{n=1}^\infty (-1)^{n+1} \frac{x^{n+1}}{n(n+1)} + C.

  1. Radius of convergence: R=1R = 1.

  2. Interval of convergence: (1,1)(-1, 1).


Would you like further details or examples? Here are some related questions for exploration:

  1. What is the Taylor expansion for ln(1x)\ln(1-x), and how does it differ?
  2. How would the result change if we integrated ln(1+x2)\ln(1+x^2) instead?
  3. Can we express the series in terms of definite integrals, such as 0xln(1+t)dt\int_0^x \ln(1+t) \, dt?
  4. What happens if you shift the center of the power series (e.g., expand around x=ax=a)?
  5. How can you verify convergence at the boundary points more rigorously?

Tip: When integrating series term by term, always verify the radius of convergence after integration!

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Math Problem Analysis

Mathematical Concepts

Calculus
Power Series
Integration
Convergence of Series

Formulas

ln(1+x) = ∑_{n=1}^∞ (-1)^{n+1} (x^n / n), |x| < 1
∫ x^n dx = x^{n+1} / (n+1)

Theorems

Taylor Series Expansion for ln(1+x)
Radius and Interval of Convergence

Suitable Grade Level

Undergraduate Mathematics