Math Problem Statement

Give the answer

x - x^2/2 + x^3/3 - x^4/4 + ... (if x < 1)

Solution

The given series is:

xx22+x33x44+(if x<1)x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \cdots \quad (\text{if } x < 1)

This is a power series, and it resembles the expansion for the natural logarithm function, specifically for ln(1+x)\ln(1+x).

The general form of the power series for ln(1+x)\ln(1+x) is:

ln(1+x)=xx22+x33x44+\ln(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \cdots

Thus, the given series can be identified as the power series for ln(1+x)\ln(1+x), valid for x<1x < 1. Therefore, the sum of this infinite series is:

ln(1+x)\ln(1+x)

Is this what you were looking for, or do you have additional questions?

Related Questions:

  1. How does this series relate to the Taylor series expansion of ln(1+x)\ln(1+x)?
  2. What is the radius of convergence for this series?
  3. How would this series change if x>1x > 1?
  4. Can you explain how to derive the series expansion for ln(1+x)\ln(1+x)?
  5. What happens if we truncate the series after a few terms?

Tip:

Power series expansions like this one are useful for approximating complex functions in calculus and analysis!

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Math Problem Analysis

Mathematical Concepts

Power Series
Natural Logarithm

Formulas

Power series for ln(1 + x): x - x^2/2 + x^3/3 - x^4/4 + ...
Sum of an infinite power series: ln(1 + x)

Theorems

Taylor Series Expansion
Convergence Theorems

Suitable Grade Level

Grades 11-12 (Advanced Calculus/Pre-Calculus)