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The question in Hindi can be translated as follows:

Given sets \( A = \{1, 2\} \) and \( B = \{a, b, c\} \), find the total number of relations from \( A \) to \( B \).

To solve this, let's analyze the problem step-by-step.

### Solution:
1. The total number of relations from a set \( A \) to a set \( B \) is the number of possible subsets of \( A \times B \).
2. The Cartesian product \( A \times B \) represents all possible ordered pairs where the first element is from \( A \) and the second is from \( B \).

Since:
- \( A = \{1, 2\} \) (which has 2 elements)
- \( B = \{a, b, c\} \) (which has 3 elements)

The Cartesian product \( A \times B \) will have \( 2 \times 3 = 6 \) elements:
\[
A \times B = \{(1, a), (1, b), (1, c), (2, a), (2, b), (2, c)\}
\]

3. Each element in \( A \times B \) can either be included in a relation or not, meaning we have 2 choices (include or exclude) for each of the 6 pairs.
4. Therefore, the total number of possible relations from \( A \) to \( B \) is \( 2^6 = 64 \).

### Answer:
The total number of relations from \( A \) to \( B \) is \( \boxed{64} \).

Would you like more details on Cartesian products or relations? Here are some related questions you might find helpful:

1. What is the Cartesian product of two sets and how is it calculated?
2. How do you determine the number of subsets of a given set?
3. What is the difference between a function and a relation?
4. How does the size of set \( B \) affect the total number of relations from \( A \) to \( B \)?
5. Can a relation exist without any ordered pairs?

**Tip:** Remember, the number of possible relations from set \( A \) to set \( B \) is based on the number of elements in the Cartesian product \( A \times B \). Each pair in \( A \times B \) can independently either be included in or excluded from a relation, giving \( 2^{\text{number of pairs}} \).

यदि A = {1, 2}, B = {a, b, c} तो A से B में सम्बन्धों की कुल संख्या है:

Explore how to find the total number of relations from set A = {1, 2} to set B = {a, b, c}. This problem covers key concepts like Cartesian products and relations, suitable for students in Grades 9-12.

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