Math Problem Statement

Write the expression in rectangular​ form, x plus y i​, and in exponential​ form, r e Superscript i theta. left bracket 3 left parenthesis cosine StartFraction pi Over 10 EndFraction plus i sine StartFraction pi Over 10 EndFraction right parenthesis right bracket Superscript 5 Question content area bottom Part 1 The rectangular form of the given expression is    enter your response here​, and the exponential form of the given expression is    enter your response here. ​(Simplify your answers. Type exact​ answers, using pi as needed. Use integers or fractions for any numbers in the​ expressions.)

Solution

To solve this, let's go through the two parts.

We are given: (3(cosπ10+isinπ10))5\left( 3 \left( \cos \frac{\pi}{10} + i \sin \frac{\pi}{10} \right) \right)^5

This expression is in polar form. To rewrite it in rectangular form x+yix + yi and exponential form reiθre^{i\theta}, we need to simplify it step-by-step.

Step 1: Rewrite the Expression Using De Moivre's Theorem

Using De Moivre's theorem, we know that: (r(cosθ+isinθ))n=rn(cos(nθ)+isin(nθ))\left( r \left( \cos \theta + i \sin \theta \right) \right)^n = r^n \left( \cos(n\theta) + i \sin(n\theta) \right) Here:

  • r=3r = 3
  • θ=π10\theta = \frac{\pi}{10}
  • n=5n = 5

Applying De Moivre's theorem, we get: (3(cosπ10+isinπ10))5=35(cos5π10+isin5π10)\left( 3 \left( \cos \frac{\pi}{10} + i \sin \frac{\pi}{10} \right) \right)^5 = 3^5 \left( \cos \frac{5\pi}{10} + i \sin \frac{5\pi}{10} \right)

Step 2: Simplify the Magnitude and Angle

Calculate 353^5: 35=2433^5 = 243

Now, simplify the angle 5π10\frac{5\pi}{10}: 5π10=π2\frac{5\pi}{10} = \frac{\pi}{2}

Thus, our expression becomes: 243(cosπ2+isinπ2)243 \left( \cos \frac{\pi}{2} + i \sin \frac{\pi}{2} \right)

Step 3: Substitute and Simplify

Now, substitute cosπ2=0\cos \frac{\pi}{2} = 0 and sinπ2=1\sin \frac{\pi}{2} = 1: 243(0+i1)=243i243 \left( 0 + i \cdot 1 \right) = 243i

So, the rectangular form is: Rectangular form: 0+243i\text{Rectangular form: } 0 + 243i

Step 4: Write in Exponential Form

The exponential form of a complex number reiθre^{i\theta} is given by the magnitude rr and angle θ\theta.

Here:

  • The magnitude r=243r = 243
  • The angle θ=π2\theta = \frac{\pi}{2}

Thus, the exponential form is: Exponential form: 243eiπ2\text{Exponential form: } 243 e^{i \frac{\pi}{2}}

Final Answer

  • Rectangular form: 0+243i0 + 243i
  • Exponential form: 243eiπ2243 e^{i \frac{\pi}{2}}

Would you like further clarification on any step?


Follow-up Questions

  1. How do you determine the angle when using De Moivre's theorem?
  2. What is the process for converting a polar form to rectangular form?
  3. How do you compute powers of complex numbers in polar form?
  4. Why is cosπ2=0\cos \frac{\pi}{2} = 0 and sinπ2=1\sin \frac{\pi}{2} = 1?
  5. What are the uses of exponential form in complex analysis?

Tip

When working with complex numbers in polar form, De Moivre's theorem is invaluable for simplifying powers and roots.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Form
Rectangular Form
Exponential Form
De Moivre's Theorem

Formulas

De Moivre's Theorem: (r (cos(θ) + i sin(θ)))^n = r^n (cos(nθ) + i sin(nθ))
Exponential Form: re^(iθ)

Theorems

De Moivre's Theorem

Suitable Grade Level

Grades 11-12