Math Problem Statement

Plot the point (-5, 4π) in polar coordinates, and find equivalent polar coordinates (r, θ) for specific conditions: r > 0, -2π ≤ θ < 0.

Solution

The problem involves converting and finding alternate representations of a point in polar coordinates (5,4π)(-5, 4\pi) and determining its equivalent coordinates for different conditions of r>0r > 0 and 2πθ<0-2\pi \leq \theta < 0.

Part (a): Convert (5,4π)(-5, 4\pi) to r>0r > 0 and 2πθ<0-2\pi \leq \theta < 0

The initial polar point is (5,4π)(-5, 4\pi), where:

  • r=5r = -5
  • θ=4π\theta = 4\pi

To make r>0r > 0, we must reflect rr to positive and adjust θ\theta accordingly: r>0    r=5r > 0 \implies r = 5 For polar coordinates, adding or subtracting 2π2\pi from θ\theta represents the same angle. Since the current θ=4π\theta = 4\pi is too large, subtract multiples of 2π2\pi to bring it within 2πθ<0-2\pi \leq \theta < 0: θ=4π2π=2π\theta = 4\pi - 2\pi = 2\pi θ=2π2π=0\theta = 2\pi - 2\pi = 0 [ The Equivalent point (5.

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Coordinate Transformation
Angle Modulo Operations

Formulas

r > 0: Reflect r to positive and adjust θ by π
θ Modulo: Add or subtract multiples of 2π to θ to adjust range

Theorems

Polar Coordinate Equivalence: (r, θ) and (-r, θ + π) represent the same point

Suitable Grade Level

Grades 10-12