Math Problem Statement

I've established the answer is D, I just need to fill in the box.

I've established the answer is D, I just need to fill in the box.

Solution

To fill in the box for part (a), we need to find a new polar representation of the point (4,3π)(-4, 3\pi) where r>0r > 0 and 2πθ<0-2\pi \leq \theta < 0.

Step-by-step solution:

  1. Understand the current coordinates:

    • The point is (4,3π)(-4, 3\pi), meaning the radius r=4r = -4 and the angle θ=3π\theta = 3\pi.
  2. Convert to a positive radius:

    • If r>0r > 0, we need to add π\pi to the angle to represent the same point with a positive rr. Thus: θ=3ππ=2π\theta = 3\pi - \pi = 2\pi

    • However, 2π2\pi is not within the required interval 2πθ<0-2\pi \leq \theta < 0. So, subtract 2π2\pi from the angle: θ=2π2π=0\theta = 2\pi - 2\pi = 0

  3. Verify the new coordinates:

    • With r=4r = 4 and θ=0\theta = 0, the point is represented in polar form as (4,0)(4, 0).

Final Answer:

(4,0)(4, 0)

If you need further clarification or want to verify additional conditions, feel free to ask!

Follow-Up Questions:

  1. How do we know the angle adjustment keeps the point equivalent in polar coordinates?
  2. Why is the negative radius important for certain polar representations?
  3. Could there be other equivalent coordinates for this point?
  4. How do periodic properties of angles in polar coordinates help in conversions?
  5. What is the geometric reasoning behind changing rr and θ\theta?

Tip:

Always verify the angle is within the specified range when adjusting polar coordinates!

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Angle Adjustment
Radius Conversion

Formulas

θ_new = θ ± 2πn
r_new = -r, θ_new = θ ± π

Theorems

Equivalence of Polar Coordinates
Properties of Angle Periodicity

Suitable Grade Level

Grades 10-12