. PHYSICS Ali is pushing a construction barrel up a ramp 1.5 meters long into the back of a truck. She is using a force of 534 newtons and the ramp is 25 deg from the horizontal. How much work in joules is Ali doing?

To calculate the work done by Ali, we use the following formula for work:

\[
W = F \cdot d \cdot \cos(\theta)
\]

Where:
- \( W \) is the work done in joules (J),
- \( F \) is the force applied (in newtons, N),
- \( d \) is the distance over which the force is applied (in meters, m),
- \( \theta \) is the angle between the force and the direction of motion (in degrees).

Given:
- \( F = 534 \, \text{N} \),
- \( d = 1.5 \, \text{m} \),
- \( \theta = 25^\circ \).

Now we plug in the values:

\[
W = 534 \, \text{N} \times 1.5 \, \text{m} \times \cos(25^\circ)
\]

Let's calculate the value.The work done by Ali is approximately \( 725.95 \, \text{J} \) (joules).

Would you like more details on how this was calculated, or do you have any further questions?

Here are 5 related questions:
1. How does the angle of the ramp affect the work done?
2. What would happen to the work if the ramp was steeper, say 35 degrees?
3. How would changing the length of the ramp affect the work done?
4. What is the relationship between work and energy in this scenario?
5. How would the work done change if friction were involved?

**Tip:** When calculating work, the angle between the force and the direction of motion is critical—if the force is perpendicular to the direction of motion, no work is done.

PHYSICS Ali is pushing a construction barrel up a ramp 1.5 meters long into the back of a truck. She is using a force of 534 newtons and the ramp is 25 deg from the horizontal. How much work in joules is Ali doing?

Learn how to calculate the work done by applying a force to push a barrel up a ramp. This problem involves physics concepts like force, work, and trigonometry. The formula used is W = F · d · cos(θ), with a force of 534 N, distance of 1.5 m, and angle of 25°. Suitable for students in Grades 9-12.

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