To calculate the approximate amount of work done by the person to move the object to the top of the incline, we use the work formula:

$W = F \cdot d \cdot \cos(\theta)$

Where:

• $F = 158.4 \, \text{N}$ (force exerted by the person parallel to the incline),
• $d = 7 \, \text{m}$ (length of the incline),
• $\theta = 0^\circ$ since the force is parallel to the incline, making $\cos(0^\circ) = 1$.

Now calculate:

$W = 158.4 \cdot 7 \cdot 1 = 1108.8 \, \text{J}$

The approximate work done by the person is 1108.8 Joules.

Would you like further details or have any questions?

Related Questions:

1. How does the angle of the incline affect the force required to move an object?
2. What role does friction play if it’s not negligible in such a setup?
3. How would the work change if the ramp length increased but the incline angle stayed the same?
4. How is the power requirement affected if the object moves faster?
5. Can you explain how potential energy relates to work in this scenario?

Tip:

Always consider the angle between the force direction and the displacement to properly apply the work formula.