Math Problem Statement

6p2

Solution

The notation 6P26P2 represents a permutation, which calculates the number of ways to arrange 2 objects from a set of 6 distinct objects.

The formula for permutations is:

nPr=n!(nr)!nP r = \frac{n!}{(n-r)!}

Where:

  • n=6n = 6
  • r=2r = 2

Substituting the values into the formula:

6P2=6!(62)!=6!4!6P2 = \frac{6!}{(6-2)!} = \frac{6!}{4!}

Now, calculate the factorials:

  • 6!=6×5×4×3×2×1=7206! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720
  • 4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24

Thus:

6P2=72024=306P2 = \frac{720}{24} = 30

So, 6P2=306P2 = 30.

Would you like more details or have any questions?

Here are 5 related questions:

  1. What is the difference between permutations and combinations?
  2. How do you calculate nCrnCr (combinations)?
  3. How does the formula change for permutations with repetition allowed?
  4. Can you explain when to use permutations versus combinations?
  5. What is 6P36P3 and how does it compare to 6P26P2?

Tip: When calculating permutations, order matters—always keep this in mind when deciding whether to use permutations or combinations!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Permutations
Factorials

Formulas

nPr = n! / (n - r)!

Theorems

Permutation formula

Suitable Grade Level

Grades 9-12