It looks like you are asking for the value of the permutation $P(8,6)$.

The formula for permutations is given by:

$P(n, r) = \frac{n!}{(n - r)!}$

For $P(8, 6)$, this becomes:

$P(8, 6) = \frac{8!}{(8 - 6)!} = \frac{8!}{2!}$

Now, let’s calculate this step by step:

1. $8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40320$
2. $2! = 2 \times 1 = 2$
3. Now, divide the two results: $\frac{40320}{2} = 20160$

So, $P(8, 6) = 20,160$.

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:

1. What is the difference between permutations and combinations?
2. How would $P(8, 3)$ be calculated?
3. Can you explain why $P(n, n)$ equals $n!$?
4. How do permutations apply in real-life scenarios, such as seating arrangements?
5. What is the value of $C(8,6)$, the combination of 8 items taken 6 at a time?

Tip: Permutations are used when the order of items matters, unlike combinations where the order doesn't matter.