Math Problem Statement

What do we mean by​ permutations? Explain the meaning of each of the terms in the permutations formula. Give an example of the​ formula's use.

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Part 1

Permutations occur whenever

▼   all selections come from a single group of items,

all items in a single group are selected,

▼   each item is selected exactly once,

items may be selected more than once,

no item may be selected more than once,

and the order of arrangement

▼   does not matter.

matters.

Solution

Part 1: What do we mean by permutations?

Permutations refer to the different ways in which a set of items can be arranged, where the order of the arrangement matters. Specifically, in permutations:

  • We are selecting items from a single group.
  • Each item is used exactly once.
  • No item can be selected more than once.
  • The order in which we arrange the items is important (i.e., [A, B] is different from [B, A]).

Permutations are common when you are arranging objects or people in a line, or when selecting winners for first, second, and third places, where the rank or order matters.

Part 2: Terms in the Permutations Formula

The formula for permutations is given by:

P(n,r)=n!(nr)!P(n, r) = \frac{n!}{(n - r)!}

where:

  • nn = the total number of items available.
  • rr = the number of items being selected or arranged.
  • n!n! = "n factorial," which is the product of all integers from 1 up to nn (i.e., n!=n×(n1)××2×1n! = n \times (n - 1) \times \dots \times 2 \times 1).
  • (nr)!(n - r)! = "factorial of nrn - r," representing the number of ways to arrange the leftover nrn - r items.

Explanation of the Formula

The formula essentially calculates how many different ways you can choose and arrange rr items from nn distinct items, considering that the order matters.

  1. n!n! represents the total number of ways to arrange all nn items.
  2. (nr)!(n - r)! accounts for the fact that after selecting rr items, we no longer care about arranging the remaining nrn - r items, so we divide by (nr)!(n - r)!.

Example of Using the Formula

Let's say you have 5 books, and you want to arrange 3 of them on a shelf. How many different ways can you arrange these 3 books?

Here, n=5n = 5 and r=3r = 3.

Using the formula:

P(5,3)=5!(53)!=5!2!P(5, 3) = \frac{5!}{(5 - 3)!} = \frac{5!}{2!}

First, calculate the factorials:

5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120 2!=2×1=22! = 2 \times 1 = 2

Now, divide:

P(5,3)=1202=60P(5, 3) = \frac{120}{2} = 60

So, there are 60 different ways to arrange 3 books from a selection of 5.


Do you have any questions or would you like more details?

Here are 5 related questions to expand on this topic:

  1. What is the difference between permutations and combinations?
  2. How would the formula change if items can be repeated in the arrangement?
  3. Can you explain how factorials work in greater detail?
  4. What is an example where permutations would be applied in a real-world scenario?
  5. How can the concept of permutations be extended to circular arrangements?

Tip: When calculating factorials for large numbers, use a calculator or software tools to avoid manual errors!

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Math Problem Analysis

Mathematical Concepts

Permutations
Factorials
Arrangements
Combinatorics

Formulas

P(n, r) = n! / (n - r)!

Theorems

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Suitable Grade Level

Grades 9-12