Math Problem Statement

Let A = {a1,...,an} be a set with n ≥ 3 elements and let c ̸∈ A. Construct a graph G = (V, E) as follows. The set of vertices is V = A ∪ {c} and the set of edges E is defined by • The sub-graph of G induced by A is a cycle. • There is an edge between c and every vertex in A. • There are no other edges except those specified above. (a) Express the number of paths of length 2 in G in terms of n. Justify your answer. (b) Express the number of cycles in G in terms of n. Justify your answer. Can you use c is the middle point and c is the end point to solve this problem? Can you discuss when c is middle point and c is end point

Solution

Let’s analyze the structure of the graph G=(V,E)G = (V, E) given in the problem and answer each question systematically.

  1. Graph Structure:
    • Vertices: The set of vertices V=A{c}V = A \cup \{c\} has n+1n+1 vertices, where A={a1,,an}A = \{a_1, \ldots, a_n\} is a set of nn vertices and cAc \notin A is an additional vertex.
    • Edges:
      • The vertices in AA form a cycle, which means each vertex aia_i is connected to ai+1a_{i+1}, and the last vertex ana_n is connected back to a1a_1.
      • The vertex cc is connected to every vertex in AA, making it a central point in the graph that connects to all other vertices in AA.
      • No other edges exist in GG.

Given this structure, let’s answer parts (a) and (b) in detail.

Part (a): Number of Paths of Length 2

A path of length 2 is a sequence of three vertices (v1,v2,v3)(v_1, v_2, v_3) where (v1,v2)E(v_1, v_2) \in E and (v2,v3)E(v_2, v_3) \in E. We will calculate the number of such paths by considering two cases based on the position of cc.

Case 1: cc as the Middle Point

If cc is the middle vertex of the path, we have a path (ai,c,aj)(a_i, c, a_j) where both aia_i and aja_j are vertices in AA, and they are distinct since no self-loops are allowed. For each aia_i in AA, we can pair it with any other aja_j in AA, giving us n(n1)n(n - 1) paths of this type.

Case 2: cc as the End Point

If cc is an endpoint of the path, we have two possibilities:

  1. The path is (c,ai,ai+1)(c, a_i, a_{i+1}) for each edge (ai,ai+1)(a_i, a_{i+1}) in the cycle of AA.
  2. The path is (ai,ai+1,c)(a_i, a_{i+1}, c) for each edge (ai,ai+1)(a_i, a_{i+1}) in the cycle of AA.

Since there are nn edges in the cycle of AA, we have 2n2n paths of this type (one for each direction).

Total Number of Paths of Length 2

Adding up the paths from both cases, we get: Total paths of length 2=n(n1)+2n=n2\text{Total paths of length 2} = n(n - 1) + 2n = n^2

Part (b): Number of Cycles in GG

A cycle is a closed path where the starting and ending vertices are the same, and each edge is used exactly once.

Case 1: Cycles in AA

Since AA forms a simple cycle by itself, there is exactly one cycle involving only the vertices in AA: a1a2ana1a_1 \to a_2 \to \ldots \to a_n \to a_1

Case 2: Cycles Including cc as a Vertex

To form a cycle that includes cc, we can pick any two distinct vertices aia_i and aja_j from AA and construct a cycle (ai,c,aj,ai1,,aj)(a_i, c, a_j, a_{i-1}, \ldots, a_j).

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Graph Theory
Combinatorics
Cycles
Paths

Formulas

Number of paths of length 2 = n^2
Number of cycles = n + 1

Theorems

Cycle Theorem
Path Counting in Graphs

Suitable Grade Level

Grades 11-12