Math Problem Statement

Let A = {a1,...,an} be a set with n ≥ 3 elements and let c ̸∈ A. Construct a graph G = (V, E) as follows. The set of vertices is V = A ∪ {c} and the set of edges E is defined by • The sub-graph of G induced by A is a cycle. • There is an edge between c and every vertex in A. • There are no other edges except those specified above. (a) Express the number of paths of length 2 in G in terms of n. Justify your answer. (b) Express the number of cycles in G in terms of n. Justify your answer. Can you use c is the middle point and c is the end point to solve this problem? Can you discuss when c is middle point and c is end point

Solution

Let's break down the construction and analyze the questions:

Part (a): Number of Paths of Length 2 in GG

  1. Understanding Paths of Length 2: A path of length 2 is a sequence of three vertices (v1,v2,v3)(v_1, v_2, v_3) where v1v_1 is connected to v2v_2 and v2v_2 is connected to v3v_3. Thus, we need to count all such sequences in GG.

  2. Types of Paths:

    • Case 1: Paths where cc is the middle vertex. For a path of length 2 with cc as the middle vertex, we have:

      • Start at a vertex aia_i in AA, go to cc, then go to another vertex aja_j in AA.
      • For each pair (ai,aj)(a_i, a_j) in AA, there is such a path. Since there are nn choices for aia_i and n1n-1 remaining choices for aja_j, this gives a total of n(n1)n(n - 1) paths of this type.
    • Case 2: Paths within the cycle induced by AA (i.e., not involving cc). Each vertex in AA has two neighbors in the cycle, so for each aia_i, there are two paths of length 2 that pass through it. This yields 2n2n paths in this case (as there are nn vertices in AA, and each has two such paths).

  3. Total Number of Paths of Length 2: n(n1)+2n=n2n(n - 1) + 2n = n^2

Thus, the total number of paths of length 2 in GG is n2\boxed{n^2}.

Part (b): Number of Cycles in GG

  1. Understanding Cycles in GG: A cycle in a graph is a closed path where the starting and ending vertices are the same, and no other vertices are repeated. In this graph, cycles can form either within the set AA or by including the vertex cc.

  2. Types of Cycles:

    • Case 1: Cycles within AA. Since AA induces a cycle, there is exactly one nn-cycle among the vertices in AA, namely a1a2ana1a_1 \to a_2 \to \dots \to a_n \to a_1.

    • Case 2: Cycles involving cc. For each pair (ai,aj)(a_i, a_j) of distinct vertices in AA, we can form a 3-cycle (ai,c,aj,ai)(a_i, c, a_j, a_i). The number of such pairs (ai,aj)(a_i, a_j) is (n2)=n(n1)2\binom{n}{2} = \frac{n(n - 1)}{2}, so there are n(n1)2\frac{n(n - 1)}{2} 3-cycles of this type.

  3. Total Number of Cycles: 1+n(n1)21 + \frac{n(n - 1)}{2}

Therefore, the total number of cycles in GG is 1+n(n1)2\boxed{1 + \frac{n(n - 1)}{2}}.

Discussion of cc as Middle Point and End Point

  • When cc is the middle point: This scenario occurs in paths of length 2 where the path starts and ends at vertices in AA with cc in between (i.e., paths of the form (ai,c,aj)(a_i, c, a_j) for distinct ai,aja_i, a_j in AA). These paths contribute to the count of paths of length 2 discussed in Part (a).

  • When cc is the end point: This scenario doesn’t contribute to the length 2 paths as defined in the problem (since they require paths with two edges and therefore an intermediate vertex). However, it does contribute to the construction of the graph GG by connecting each vertex in AA to cc, enabling the formation of cycles and certain paths.

Would you like further clarification on any part?

Here are five related questions:

  1. What would change if we allowed self-loops in the graph GG?
  2. How would the total path and cycle counts differ if GG was directed?
  3. Can you find a general formula for paths of length kk in this graph?
  4. What other properties of GG can we infer from this structure (e.g., connectivity, bipartiteness)?
  5. How does the structure of GG change if we add more vertices connected only to cc?

Tip: When analyzing paths in a graph, breaking them down by cases (such as which vertex serves as the middle) can simplify calculations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Graph Theory
Paths
Cycles
Combinatorics

Formulas

Paths of length 2: n(n - 1) + 2n = n^2
Cycles: 1 + n(n - 1)/2

Theorems

Cycle in a Graph
Counting Paths

Suitable Grade Level

College Level