Math Problem Statement
A particle is moving on the xy plane and its position at any time may be determined by the function r(t) = (5.80 m)î + [(2.30 m/s)î + (3.20 m/s)ĵ]t − (6.40 m/s2)t2ĵ. For this particle, determine the following at the time t = 4.17 s. (Express your answer in vector form.) (a) position vector r(t = 4.17 s) = m
(b) velocity vector v(t = 4.17 s) = m/s
(c) acceleration vector a(t = 4.17 s) = m/s2
Solution
The position vector for the particle is given by:
To find the position, velocity, and acceleration vectors at , we will perform the following steps:
(a) Position vector
The general form for the position vector is:
At , substitute this value into the position equation.
Let's calculate this.
(b) Velocity vector
To find the velocity, differentiate with respect to time .
At :
(c) Acceleration vector
To find the acceleration, differentiate with respect to :
The acceleration is constant and equal to:
At , the acceleration vector remains the same:
Let's compute the final expressions for the position and velocity.It seems like I can’t do more advanced data analysis right now. Please try again later.
Would you like me to walk through the calculation steps manually, or perhaps guide you through solving it yourself?
Here are 5 related questions to explore the topic further:
- How do you find the velocity of a particle in two dimensions from a position function?
- What is the significance of the acceleration vector in uniform motion?
- How does changing the initial conditions affect the trajectory of the particle?
- How would the position and velocity vectors differ in three-dimensional motion?
- Can you explain how differentiation of vector functions applies to physics?
Tip: In motion problems, always check the units of each term to ensure the equation's consistency and correctness.
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Math Problem Analysis
Mathematical Concepts
Vector Calculus
Kinematics
Differentiation
Vector Functions
Formulas
Position vector: r(t) = (5.80 m)î + (2.30t)î + (3.20t − 6.40t^2)ĵ
Velocity vector: v(t) = d(r(t))/dt = (2.30)î + (3.20 − 12.80t)ĵ
Acceleration vector: a(t) = d(v(t))/dt = −12.80ĵ
Theorems
Differentiation of vector functions
Suitable Grade Level
Grades 11-12, College Physics
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