Math Problem Statement

The partial fraction decomposition of x^2+7/x^3+5x^2 can be written in the form of f(x)/x+g(x)/x^2+h(x)/x+5 solve for f(x), g(x) and h(x)

Solution

To perform the partial fraction decomposition of the given rational expression:

x2+7x3+5x2,\frac{x^2 + 7}{x^3 + 5x^2},

the denominator x3+5x2x^3 + 5x^2 can be factored as:

x3+5x2=x2(x+5).x^3 + 5x^2 = x^2(x + 5).

Thus, the expression can be decomposed into:

x2+7x3+5x2=f(x)x+g(x)x2+h(x)x+5.\frac{x^2 + 7}{x^3 + 5x^2} = \frac{f(x)}{x} + \frac{g(x)}{x^2} + \frac{h(x)}{x + 5}.

Here, f(x),g(x),h(x)f(x), g(x), h(x) are constants, since the degree of the numerators in the partial fractions must be less than the degree of their respective denominators.

Step 1: Write the equation

Start with:

x2+7x3+5x2=Ax+Bx2+Cx+5.\frac{x^2 + 7}{x^3 + 5x^2} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 5}.

Step 2: Combine the fractions

Multiply through by the denominator x3+5x2=x2(x+5)x^3 + 5x^2 = x^2(x + 5) to eliminate the fractions:

x2+7=Ax(x+5)+B(x+5)+Cx2.x^2 + 7 = A x(x + 5) + B(x + 5) + Cx^2.

Step 3: Expand the terms

Expand the right-hand side:

x2+7=A(x2+5x)+B(x+5)+Cx2.x^2 + 7 = A(x^2 + 5x) + B(x + 5) + Cx^2.

Simplify:

x2+7=Ax2+5Ax+Bx+5B+Cx2.x^2 + 7 = Ax^2 + 5Ax + Bx + 5B + Cx^2.

Group like terms:

x2+7=(A+C)x2+(5A+B)x+5B.x^2 + 7 = (A + C)x^2 + (5A + B)x + 5B.

Step 4: Equate coefficients

Equate the coefficients of x2x^2, xx, and the constant term on both sides:

  1. Coefficient of x2x^2: A+C=1A + C = 1,
  2. Coefficient of xx: 5A+B=05A + B = 0,
  3. Constant term: 5B=75B = 7.

Step 5: Solve the system of equations

  1. From 5B=75B = 7, solve for BB: B=75.B = \frac{7}{5}.

  2. Substitute B=75B = \frac{7}{5} into 5A+B=05A + B = 0: 5A+75=0    5A=75    A=725.5A + \frac{7}{5} = 0 \implies 5A = -\frac{7}{5} \implies A = -\frac{7}{25}.

  3. Use A+C=1A + C = 1 to solve for CC: 725+C=1    C=1+725=2525+725=3225.-\frac{7}{25} + C = 1 \implies C = 1 + \frac{7}{25} = \frac{25}{25} + \frac{7}{25} = \frac{32}{25}.

Final Values

The coefficients are:

f(x)=A=725,g(x)=B=75,h(x)=C=3225.f(x) = A = -\frac{7}{25}, \quad g(x) = B = \frac{7}{5}, \quad h(x) = C = \frac{32}{25}.

Final Decomposition

The partial fraction decomposition is:

x2+7x3+5x2=725x+75x2+3225x+5.\frac{x^2 + 7}{x^3 + 5x^2} = \frac{-\frac{7}{25}}{x} + \frac{\frac{7}{5}}{x^2} + \frac{\frac{32}{25}}{x + 5}.


Do you want further clarification or more examples?

Related Questions:

  1. How is partial fraction decomposition used to integrate rational functions?
  2. Can partial fraction decomposition be applied to improper fractions? If yes, how?
  3. What are the common applications of partial fractions in engineering or physics?
  4. How do you handle repeated roots in the denominator for partial fraction decomposition?
  5. What is the role of linear vs quadratic factors in partial fraction decomposition?

Tip:

Always check if the rational function is improper. If it is, perform polynomial long division before proceeding with partial fractions.

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Math Problem Analysis

Mathematical Concepts

Partial Fraction Decomposition
Algebra
Rational Expressions

Formulas

Partial Fraction Decomposition formula: \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x+5}

Theorems

Equating coefficients of like powers of x

Suitable Grade Level

Grades 10-12