 
x3
/(x2 + 7x + 6) partial fraction decomposition


To decompose the rational expression \( \frac{x^3}{x^2 + 7x + 6} \) into partial fractions, we need to follow these steps:

### Step 1: Factor the denominator
We begin by factoring the quadratic denominator:

\[
x^2 + 7x + 6 = (x + 1)(x + 6)
\]

### Step 2: Set up the partial fraction decomposition form
Since the denominator factors as \( (x + 1)(x + 6) \), we can express the fraction as:

\[
\frac{x^3}{(x + 1)(x + 6)} = \frac{A}{x + 1} + \frac{B}{x + 6}
\]

where \( A \) and \( B \) are constants we need to determine.

### Step 3: Multiply through by the denominator
To eliminate the denominators, multiply both sides by \( (x + 1)(x + 6) \):

\[
x^3 = A(x + 6) + B(x + 1)
\]

### Step 4: Expand and collect like terms
Expand both sides:

\[
x^3 = A(x + 6) + B(x + 1) = A \cdot x + 6A + B \cdot x + B
\]
\[
x^3 = (A + B) \cdot x + (6A + B)
\]

### Step 5: Set up equations by comparing coefficients
Now, compare the coefficients of \( x \) on both sides:

- From the \( x^3 \) term: There is no \( x^3 \) term on the right-hand side, which means \( A + B \) must equal zero:

  \[
  A + B = 0
  \]

- From the constant term: The constant term on the right-hand side is \( 6A + B \), and on the left-hand side, the constant is 0. So:

  \[
  6A + B = 0
  \]

### Step 6: Solve the system of equations
Now, we solve the system of two equations:

1. \( A + B = 0 \)
2. \( 6A + B = 0 \)

From the first equation, \( B = -A \). Substitute this into the second equation:

\[
6A - A = 0 \implies 5A = 0 \implies A = 0
\]

Since \( A = 0 \), from the first equation, \( B = 0 \).

### Step 7: Conclusion
In this case, the partial fraction decomposition simplifies to:

\[
\frac{x^3}{(x + 1)(x + 6)} = 0
\]

This indicates there is no non-trivial partial fraction decomposition for this expression, and the original fraction remains as-is.

---

Do you have any questions or would you like further clarification?

Here are some related questions to explore:

1. How does partial fraction decomposition work for higher-degree polynomials?
2. Can partial fraction decomposition be applied to improper fractions?
3. What happens when the degree of the numerator is greater than the denominator?
4. How do you apply partial fraction decomposition to repeated factors?
5. How does partial fraction decomposition apply to rational functions with complex roots?

**Tip:** Always check if the degree of the numerator is higher than the denominator. If so, perform polynomial division first!

x^3/(x^2 + 7x + 6) partial fraction decomposition

Explore the step-by-step process to decompose x^3/(x^2 + 7x + 6) into partial fractions. This guide covers polynomial factorization, partial fraction decomposition techniques, and solving linear systems to determine constants. Ideal for high school students in Grades 10-12.

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