Math Problem Statement

Five years ago, a high-school cafeteria charged $5.85 for three pieces of fruit and a chicken salad. Today, each piece of fruit costs 12% more, while a chicken salad costs 15% more. The new cost of three pieces of fruit and a chicken salad is $6.66. Determine the new prices of a piece of fruit and a chicken salad.

Solution

Let the cost of a piece of fruit 5 years ago be denoted by ff and the cost of a chicken salad 5 years ago be denoted by ss. The problem provides the following information:

  1. Five years ago, the cost of three pieces of fruit and a chicken salad was $5.85: 3f+s=5.853f + s = 5.85
  2. Today, the cost of each piece of fruit is 12% more, and the cost of a chicken salad is 15% more. Therefore, the new cost of three pieces of fruit and a chicken salad is $6.66: 3(f×1.12)+(s×1.15)=6.663(f \times 1.12) + (s \times 1.15) = 6.66 Simplifying the second equation: 3(1.12f)+1.15s=6.663(1.12f) + 1.15s = 6.66 3.36f+1.15s=6.663.36f + 1.15s = 6.66 Now we have a system of two equations:

1)3f+s=5.851) \quad 3f + s = 5.85 2)3.36f+1.15s=6.662) \quad 3.36f + 1.15s = 6.66

Solving the system:

From the first equation, solve for ss: s=5.853fs = 5.85 - 3f

Substitute this expression for ss into the second equation: 3.36f+1.15(5.853f)=6.663.36f + 1.15(5.85 - 3f) = 6.66 Now, expand the equation: 3.36f+1.15×5.851.15×3f=6.663.36f + 1.15 \times 5.85 - 1.15 \times 3f = 6.66 3.36f+6.72753.45f=6.663.36f + 6.7275 - 3.45f = 6.66 Simplify: 0.09f+6.7275=6.66-0.09f + 6.7275 = 6.66 0.09f=6.666.7275-0.09f = 6.66 - 6.7275 0.09f=0.0675-0.09f = -0.0675 f=0.06750.09=0.75f = \frac{-0.0675}{-0.09} = 0.75 So, the price of a piece of fruit 5 years ago was f=0.75f = 0.75.

Now, substitute f=0.75f = 0.75 into the first equation: 3(0.75)+s=5.853(0.75) + s = 5.85 2.25+s=5.852.25 + s = 5.85 s=5.852.25=3.60s = 5.85 - 2.25 = 3.60

Thus, the price of a chicken salad 5 years ago was s=3.60s = 3.60.

New Prices:

  • The new price of a piece of fruit is 0.75×1.12=0.840.75 \times 1.12 = 0.84.
  • The new price of a chicken salad is 3.60×1.15=4.143.60 \times 1.15 = 4.14.

Therefore, the new prices are:

  • A piece of fruit costs $0.84.
  • A chicken salad costs $4.14.

Would you like further details or have any questions?

Here are 5 related questions:

  1. What would the total cost be if you purchased 5 pieces of fruit and 2 chicken salads today?
  2. How much did the price of a single chicken salad increase over the 5-year period?
  3. What is the percentage increase in the total price from $5.85 to $6.66?
  4. If fruit prices continue to increase by 12% every 5 years, what will a piece of fruit cost in another 5 years?
  5. How would the system change if the fruit price increase was 10% instead of 12%?

Tip: When dealing with percentage changes, multiplying the original value by 1+percentage change1 + \text{percentage change} (in decimal form) is a quick way to find the new value.

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Math Problem Analysis

Mathematical Concepts

Algebra
Percentage Increase
Systems of Equations

Formulas

3f + s = 5.85
3.36f + 1.15s = 6.66
Price Increase Formula: New Price = Old Price * (1 + Percentage Increase)

Theorems

Linear Equation Solving
System of Equations Substitution

Suitable Grade Level

Grades 9-11