Math Problem Statement

HW 27_ Optimization Problems - Part II (4.5)-Sasha Sam.pdf

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A boat on the ocean is 3 miles from the nearest point on a straight shoreline; that point is 9 miles from a restaurant on the shore. A woman plans to row the boat straight to a point on the shore and then walk along the shore to the restaurant. Complete parts (a) and (b): (a) If she walks at 3 mi/hr and rows at 2 mi/hr, at which point on the shore should she land to minimize the total travel time? (b) If she walks at 3 mi/hr, what is the minimum speed at which she must row so that the quickest way to the restaurant is to row directly (with no walking)?

Solution

The solution to the problem involves determining the optimal location for landing the boat and the minimum rowing speed required for the shortest time.

Part (a): Finding the Optimal Landing Point

  1. Set Up Variables and Function for Total Time:

    • Let xx be the distance from point AA (the nearest shore point to the boat) to the landing point on the shore.
    • The distance she rows to the shore is x2+9\sqrt{x^2 + 9}, and the distance she walks to the restaurant is 9x9 - x.
  2. Time Function:

    • The total travel time T(x)T(x) is given by the sum of the time rowing and walking: T(x)=x2+92+9x3T(x) = \frac{\sqrt{x^2 + 9}}{2} + \frac{9 - x}{3}
    • This equation combines both the rowing and walking segments based on their respective speeds.
  3. Find Critical Points:

    • Differentiate T(x)T(x) with respect to xx, set T(x)=0T'(x) = 0, and solve for xx.
    • In this case, the solution yields x=655x = \frac{6\sqrt{5}}{5} miles from point AA, or equivalently, 96559 - \frac{6\sqrt{5}}{5} miles from the restaurant.

Part (b): Minimum Rowing Speed for Direct Route

  1. Set Up Condition for Direct Rowing:

    • For the fastest route directly to the restaurant, we want to set x=9x = 9, and we solve for the minimum rowing speed, rr, so that rowing directly takes less time than the combined rowing and walking.
  2. Determine Minimum Rowing Speed:

    • Solving with given conditions, we find that r=15292.79r = \frac{15}{\sqrt{29}} \approx 2.79 mi/hr.

This approach should match the given answers in the problem. Let me know if you need more clarification or a step-by-step breakdown.


Would you like more details on a specific step or concept? Here are related questions to deepen understanding:

  1. How does changing the walking speed affect the optimal landing point?
  2. What is the significance of the critical point in optimization problems like this?
  3. How would the time equation change if the rowing speed were faster than the walking speed?
  4. Can this method be applied to other similar distance minimization problems?
  5. What would happen if the destination were at a different point on the shore?

Tip: In optimization problems, setting up equations carefully and identifying constraints help streamline the solution process.

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Math Problem Analysis

Mathematical Concepts

Optimization
Differentiation
Pythagorean Theorem

Formulas

Time function: T(x) = (sqrt(x^2 + 9) / rowing speed) + ((9 - x) / walking speed)
Derivative to find critical points
Solving for minimum speed in part (b)

Theorems

Pythagorean Theorem
First Derivative Test

Suitable Grade Level

College-level Calculus