Math Problem Statement
Question content area top Part 1 A boat on the ocean is 3 mi from the nearest point on a straight shoreline; that point is 13 mi from a restaurant on the shore. A woman plans to row the boat straight to a point on the shore and then walk along the shore to the restaurant. Complete parts (a) and (b) below. 3 mi 13 mi Question content area bottom Part 1 a. If she walks at 3 mi/hr and rows at 2 mi/hr, at which point on the shore should she land to minimize the total travel time? To minimize the total travel time, the boat should land enter your response here miles from the restaurant. (Type an exact answer, using radicals as needed.) Part 2 b. If she walks at 3 mi/hr, find the minimum speed at which she must row so that the quickest way to the restaurant is to row directly (with no walking)? The minimum speed she must row is enter your response here mi/hr. (Type an exact answer, using radicals as needed.)
Solution
Problem Breakdown
Let’s analyze each part of the problem systematically.
Part 1 (a): Minimize Total Travel Time
Let:
- : Distance from the landing point on the shore to the restaurant sympy import symbols, sqrt, diff, solve
Define variables
x = symbols('x', positive=True) # Distance from the landing point to the restaurant d_boat_to_shore = 3 # Distance from boat to shore d_shore_to_restaurant = 13 # Total distance along the shore
Speeds
v_row = 2 # Rowing speed (mi/hr) v_walk = 3 # Walking speed (mi/hr)
Time equations
time_row = sqrt(d_boat_to_shore2 + x2) / v_row # Time to row to landing point time_walk = (d_shore_to_restaurant - x) / v_walk # Time to walk to the restaurant
Total time
total_time = time_row + time_walk
Minimize total time
time_derivative = diff(total_time, x) # Derivative of time w.r.t. x optimal_x = solve(time_derivative, x) # Solve for critical points
optimal_xThe optimal landing point on the shore is approximately:
This is the point where the total travel time is minimized.
Part 1 (b): Minimum Speed to Row Directly
Here, the woman rows directly without walking. We need to find the rowing speed such that rowing directly is faster than the combined time of rowing and walking for any landing point.
Let’s calculate this: Direct rowing distance direct_distance = sqrt(d_boat_to_shore2 + d_shore_to_restaurant2) # Hypotenuse
Time to row directly
time_row_direct = direct_distance / v_row
Set condition: rowing directly must be equal or faster than combined time
v_row_min = symbols('v_row_min', positive=True) time_row_direct_new = direct_distance / v_row_min row_walk_time_combined = total_time.subs(x, optimal_x[0]) # Combined time at optimal point
Solve for minimum rowing speed
min_rowing_speed = solve(time_row_direct_new - row_walk_time_combined, v_row_min) min_rowing_speedThe minimum speed at which she must row directly (without walking) to ensure the quickest way to the restaurant is:
This is the exact expression for the required speed. If you'd like, I can calculate an approximate numerical value for better clarity. Let me know!
Do you want further details or have any questions?
Relative Questions:
- What is the numerical approximation of the optimal landing point distance?
- How do walking and rowing speeds affect the optimal point?
- What would happen if the walking speed were slower than the rowing speed?
- How can the optimal solution be graphed to visualize travel times?
- What practical considerations might alter the theoretical optimal solution?
Tip: When solving optimization problems, always verify critical points and boundary conditions to ensure you find the global minimum.
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Math Problem Analysis
Mathematical Concepts
Optimization
Pythagorean Theorem
Derivative Calculus
Rate-Time-Distance Relationships
Formulas
Pythagorean Theorem: c^2 = a^2 + b^2
Time = Distance / Speed
Derivative for optimization: f'(x) = 0 to find critical points
Theorems
Pythagorean Theorem
Critical Point Theorem for Minima
Suitable Grade Level
Grades 11-12, Undergraduate
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