https://file.aiquickdraw.com/mathbot/file/17260825944645eo2hphz.jpg

It seems like I can’t do more advanced data analysis right now. Please try again later. However, I can still help you solve the complex multiplication from the image. Let's break it down manually.

You need to multiply the complex numbers \((-6 - 8i)\) and \((3 + 4i)\).

To multiply two complex numbers, we apply the distributive property (similar to multiplying two binomials) and simplify:

\[
(-6 - 8i)(3 + 4i) = (-6)(3) + (-6)(4i) + (-8i)(3) + (-8i)(4i)
\]

Now let's calculate each part:

1. \((-6)(3) = -18\)
2. \((-6)(4i) = -24i\)
3. \((-8i)(3) = -24i\)
4. \((-8i)(4i) = -32i^2\), and since \(i^2 = -1\), this becomes \(-32(-1) = 32\)

Now, combine all the terms:
\[
-18 - 24i - 24i + 32
\]
Simplify:
\[
(-18 + 32) + (-24i - 24i) = 14 - 48i
\]

So, the product of the two complex numbers is:

\[
14 - 48i
\]

Let me know if you need further explanation or have any questions!

Here are 5 related questions:
1. How do you add and subtract complex numbers?
2. How do you find the modulus of a complex number?
3. What is the conjugate of a complex number, and how is it used?
4. How do you divide complex numbers?
5. How are complex numbers represented graphically?

**Tip:** Always remember that \(i^2 = -1\) when multiplying complex numbers!

Multiply the complex numbers (-6 - 8i)(3 + 4i)

Learn how to multiply the complex numbers (-6 - 8i) and (3 + 4i) using the distributive property and simplifying the result. This solution breaks down the problem step by step, explaining how to apply key concepts like i^2 = -1. Suitable for students in Grades 10-12.

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