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### Part 1:
The rental car company charges $45 as a base fee, plus 15 cents per mile. This means the total cost $ C $ is composed of two parts:
- A fixed cost of $45
- A variable cost of 15 cents (or $0.15) for every mile driven $ m $

This can be written as:
\[
C = 45 + 0.15m
\]

So, the correct option for Part 1 is:
- $ C = 0.15m + 45 $

### Part 2:
To find the total cost for driving 150 miles, we substitute $ m = 150 $ into the equation:

\[
C = 45 + 0.15(150)
\]
\[
C = 45 + 22.50
\]
\[
C = 67.50
\]

Thus, the total cost of driving 150 miles is **$67.50**.

Would you like further details or have any questions about these steps?

Here are 5 additional questions to expand your understanding:
1. How would the equation change if the rental company charged 20 cents per mile instead?
2. If you were to drive 200 miles, what would the total cost be?
3. How does the fixed cost affect the total cost compared to the per-mile cost?
4. What would the equation look like if the company offered a $5 discount on the fixed fee?
5. How would the total cost change if the per-mile rate were doubled?

**Tip:** Always break down word problems into smaller parts: identify fixed and variable costs to build an equation.

A rental car company charges $45 plus 15 cents per mile driven. Part 1, Which of the following could be used to model the total cost of the rental where m represents the miles driven: C = 15m + 45, C = 0.15m + 45, or C = 1.5m + 45? Part 2, The total cost of driving 150 miles is: $______

Learn how to model the total cost of a car rental using linear equations. This problem involves a base fee of $45 and a per-mile cost of 15 cents. Calculate the total cost for 150 miles and understand key concepts in algebra and cost modeling. Suitable for Grades 6-8.

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