To find the midpoint of the line segment joining two points $R(4, 3)$ and $S(-3, 6)$, we use the midpoint formula:

$\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$

Here, $R(4, 3)$ gives $x_1 = 4$ and $y_1 = 3$, and $S(-3, 6)$ gives $x_2 = -3$ and $y_2 = 6$.

Now, substitute the values:

$\text{Midpoint} = \left( \frac{4 + (-3)}{2}, \frac{3 + 6}{2} \right)$

Simplify the expression:

$\text{Midpoint} = \left( \frac{1}{2}, \frac{9}{2} \right)$

Thus, the midpoint of the line segment is:

$\left( \frac{1}{2}, \frac{9}{2} \right)$

Would you like more details or have any questions?

Here are 5 related questions to expand on this concept:

1. How do you find the distance between two points in a plane?
2. What is the equation of the line passing through $R(4, 3)$ and $S(-3, 6)$?
3. How do you find the slope of the line segment joining two points?
4. What is the formula for dividing a line segment into a specific ratio?
5. How can the midpoint formula be applied in three dimensions?

Tip: Always double-check your signs when using formulas that involve coordinates to avoid simple errors.