Find the midpoint of the line segment joining the points ​R(3​,3​) and ​S(negative 2​,6​).
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Part 1
The midpoint is 
  
enter your response here.
​(Type an ordered pair. Use integers or simplified fractions for any numbers in the​ expression.)

To find the midpoint of a line segment joining two points, you use the midpoint formula:

\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Given the points \( R(3, 3) \) and \( S(-2, 6) \):

- \( x_1 = 3 \), \( y_1 = 3 \)
- \( x_2 = -2 \), \( y_2 = 6 \)

Now, substitute these values into the formula:

\[
\text{Midpoint} = \left( \frac{3 + (-2)}{2}, \frac{3 + 6}{2} \right)
\]

Simplify the expressions:

\[
\text{Midpoint} = \left( \frac{1}{2}, \frac{9}{2} \right)
\]

Therefore, the midpoint is:

\[
\left( \frac{1}{2}, \frac{9}{2} \right)
\]

Do you want more details or have any questions?

Here are some related questions to consider:
1. How do you find the distance between the points \(R\) and \(S\)?
2. What is the slope of the line passing through \(R\) and \(S\)?
3. How would you find the equation of the line passing through \(R\) and \(S\)?
4. Can you verify the midpoint by finding the average of the x-coordinates and y-coordinates separately?
5. What happens to the midpoint if both points are shifted by the same amount?

**Tip:** Always double-check your midpoint calculations by averaging the x-coordinates and y-coordinates separately.

Learn how to find the midpoint of a line segment RS with points R(3, 3) and S(-2, 6) using the midpoint formula. This problem covers coordinate geometry concepts and is suitable for students in Grades 6-8.

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