Math Problem Statement
nを2以上の整数としてfn(x)=∮(0→x)(sinnt-sint)dtとする。関数y=fn(x)の0≦x≦π/2における最大値をMnとおく。これを求めよ。
Solution
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Math Problem Analysis
Mathematical Concepts
Integral Calculus
Trigonometric Functions
Maxima of Functions
Formulas
f_n(x) = ∫(0→x)(sin(nt) - sin(t)) dt
f'_n(x) = sin(nx) + sin(x)
M_n = 1 + 1/n
Theorems
Fundamental Theorem of Calculus
Critical Points for Maxima
Suitable Grade Level
Undergraduate Mathematics or Advanced High School Calculus
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