Math Problem Statement

Q=30L^2-0,5L^3 how do you find the value of L that maximises APL

Solution

To find the value of LL that maximizes Average Product of Labor (APL), we need to first define APL and then find its maximum. The APL is defined as:

APL=QLAPL = \frac{Q}{L}

Given Q=30L20.5L3Q = 30L^2 - 0.5L^3, we can substitute this into the formula for APL:

APL=30L20.5L3LAPL = \frac{30L^2 - 0.5L^3}{L}

Simplifying the expression:

APL=30L0.5L2APL = 30L - 0.5L^2

Next, to find the maximum APL, we need to take the derivative of APL with respect to LL and set it to zero:

d(APL)dL=30L\frac{d(APL)}{dL} = 30 - L

Setting the derivative equal to zero to find the critical point:

30L=030 - L = 0

L=30L = 30

To ensure this value of L=30L = 30 is a maximum, we can check the second derivative of APL:

d2(APL)dL2=1\frac{d^2(APL)}{dL^2} = -1

Since the second derivative is negative, L=30L = 30 is indeed a maximum point for APL.

Therefore, the value of LL that maximizes APL is L=30L = 30.

Would you like more details or have any questions?

Related Questions

  1. How do you find the total product (TP) at the point where APL is maximized?
  2. What is the value of APL when L=30L = 30?
  3. How do you find the marginal product of labor (MPL) from the given production function?
  4. What is the economic interpretation of maximizing APL?
  5. How does APL change as LL increases beyond 30?

Tip: The relationship between APL and Marginal Product of Labor (MPL) is crucial in understanding the efficiency of labor inputs in production.

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Math Problem Analysis

Mathematical Concepts

Calculus
Optimization
Derivatives

Formulas

APL = Q / L
Q = 30L^2 - 0.5L^3
APL = 30L - 0.5L^2
d(APL)/dL = 30 - L

Theorems

First Derivative Test
Second Derivative Test

Suitable Grade Level

Undergraduate Economics or Calculus Level