Math Problem Statement
If 1500 square centimeters of material is available to make a box with a square base and an open top, find the largest possible volume of the box
Solution
To find the largest possible volume of a box with a square base and an open top using 1500 square centimeters of material, we need to set up and solve an optimization problem.
Step 1: Define variables
- Let be the length of one side of the square base.
- Let be the height of the box.
Step 2: Constraints and relationships
-
Surface area constraint: The box has:
- A square base with an area ,
- Four rectangular sides, each with an area .
Total surface area is:
-
Volume of the box: The volume is:
Step 3: Solve for in terms of
From the surface area equation:
Step 4: Substitute into the volume equation
Simplify:
Step 5: Maximize
Differentiate with respect to :
Set :
Step 6: Determine
Substitute into the equation for :
Step 7: Find the maximum volume
Final Answer:
The largest possible volume of the box is approximately 5590.17 cm³.
Would you like detailed explanations of any specific step?
Related Questions:
- What would happen to the volume if the material were doubled?
- How does the height of the box change if the base size changes?
- What is the relationship between surface area and volume for this shape?
- How do derivatives help in finding maximum values in such problems?
- Could the box have a closed top with the same material constraint?
Tip:
Always check the constraints carefully when solving optimization problems, as they dictate feasible solutions.
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Math Problem Analysis
Mathematical Concepts
Optimization
Derivatives
Surface Area
Volume of 3D Shapes
Formulas
Surface area constraint: x^2 + 4xh = 1500
Volume of the box: V = x^2h
Optimization condition: dV/dx = 0
Theorems
Extreme Value Theorem
First Derivative Test
Suitable Grade Level
Grades 11-12 (High School Calculus)
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