Math Problem Statement

Determine the dimensions of matrix (C + D)a, the first row, first column element, and the 500th row, first column element of (C + D)a, given matrices C, D, and vector a.

Solution

Let's analyze and solve the questions one by one based on the image provided:

Problem Summary

  1. Matrix DD: It is a diagonal matrix with elements from 1 to 2000, i.e., D=diag(1,2,3,,2000)D = \text{diag}(1, 2, 3, \dots, 2000).
  2. Matrix CC: It has mostly zero entries except for three specified values:
    • Element at row 1, column 2 is 5.
    • Element at row 499, column 499 is -8.
    • Element at row 500, column 501 is 3.
  3. Vector a\vec{a}: Defined as a=(22,23,,22000)T\vec{a} = (2^2, 2^3, \dots, 2^{2000})^T.
  4. Matrix C+DC + D: We are to consider the multiplication (C+D)a(C + D) \vec{a}.

Now, let’s go through each question in detail.

Question (a)

How many rows and columns does the matrix (C+D)a(C + D) \vec{a} have?

Since DD is a 2000x2000 diagonal matrix, CC must also be a 2000x2000 matrix (to enable addition). Therefore, C+DC + D is a 2000x2000 matrix. When we multiply (C+D)(C + D) by a\vec{a}, the resulting matrix will have the dimensions of a\vec{a}, which is a 2000x1 vector.

  • Answer: (C+D)a(C + D) \vec{a} has 2000 rows and 1 column.

Question (b)

Determine the element in the 1st row and 1st column of (C+D)a(C + D) \vec{a}.

The entry in the 1st row and 1st column of (C+D)a(C + D) \vec{a} is given by: ((C+D)a)1,1=j=12000(C+D)1,jaj((C + D) \vec{a})_{1,1} = \sum_{j=1}^{2000} (C + D)_{1,j} \cdot a_j Since CC is mostly zero except for specified entries, we only need to consider the elements affected by CC and DD.

  1. Contribution from DD: Since DD is diagonal, D1,1=1D_{1,1} = 1.
  2. Contribution from CC: Only C1,2=5C_{1,2} = 5 is non-zero in the first row.

So, we have: ((C+D)a)1,1=D1,1a1+C1,2a2=122+523=4+58=4+40=44((C + D) \vec{a})_{1,1} = D_{1,1} \cdot a_1 + C_{1,2} \cdot a_2 = 1 \cdot 2^2 + 5 \cdot 2^3 = 4 + 5 \cdot 8 = 4 + 40 = 44

  • Answer: The element in the 1st row and 1st column of (C+D)a(C + D) \vec{a} is 44.

Question (c)

Determine the element in the 500th row and 1st column of (C+D)a(C + D) \vec{a}.

The entry in the 500th row and 1st column of (C+D)a(C + D) \vec{a} is given by: ((C+D)a)500,1=j=12000(C+D)500,jaj((C + D) \vec{a})_{500,1} = \sum_{j=1}^{2000} (C + D)_{500,j} \cdot a_j Again, we only need to consider the non-zero elements in CC and DD for the 500th row.

  1. Contribution from DD: D500,500=500D_{500,500} = 500.
  2. Contribution from CC: The only non-zero element in row 500 of CC is C500,501=3C_{500,501} = 3.

So, we have: ((C+D)a)500,1=D500,500a500+C500,501a501=5002501+32502((C + D) \vec{a})_{500,1} = D_{500,500} \cdot a_{500} + C_{500,501} \cdot a_{501} = 500 \cdot 2^{501} + 3 \cdot 2^{502} Simplify 25022^{502} in terms of 25012^{501}: =5002501+3(22501)=5002501+62501=(500+6)2501=5062501= 500 \cdot 2^{501} + 3 \cdot (2 \cdot 2^{501}) = 500 \cdot 2^{501} + 6 \cdot 2^{501} = (500 + 6) \cdot 2^{501} = 506 \cdot 2^{501}

  • Answer: The element in the 500th row and 1st column of (C+D)a(C + D) \vec{a} is 5062501506 \cdot 2^{501}.

Would you like additional details or further clarification on any of these steps?

Related Questions:

  1. How would the structure of DD change if it were not a diagonal matrix?
  2. How do we handle large exponent values in calculations involving matrices and vectors?
  3. What would the result be if CC had more non-zero entries?
  4. Can the result in (c) be simplified further for computational efficiency?
  5. How does the matrix C+DC + D affect the vector a\vec{a} compared to applying DD alone?

Tip:

When working with large powers in matrix computations, always look for ways to express terms in simpler forms using properties of exponents, which can make both manual and computational work easier.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Operations
Vector Multiplication
Diagonal and Sparse Matrices

Formulas

Matrix multiplication formula: (AB)_{i,j} = Σ (A_{i,k} * B_{k,j})
Power of two series: 2^n
Matrix addition and sparse matrix handling

Theorems

Matrix multiplication and elementwise addition properties

Suitable Grade Level

Undergraduate Mathematics