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The problem asks to find \( 3B - 3A \), given the matrices \( A \) and \( B \).

### Given matrices:
\[
A = \begin{pmatrix}
6 & -1 \\
-5 & -8 \\
0 & 4
\end{pmatrix}
\quad \text{and} \quad
B = \begin{pmatrix}
-1 & -7 & -9 \\
-9 & -9 & -1
\end{pmatrix}
\]

### Step 1: Check Dimensions
Matrix \( A \) is a \( 3 \times 2 \) matrix, and matrix \( B \) is a \( 2 \times 3 \) matrix.

In order to perform \( 3B - 3A \), both matrices must have the same dimensions. Since \( A \) is \( 3 \times 2 \) and \( B \) is \( 2 \times 3 \), the subtraction is **not possible** because the dimensions are incompatible.

### Conclusion:
It is **not possible** to compute \( 3B - 3A \).

Would you like further clarification or any specific details?

### Here are five related questions:
1. What are the conditions for matrix addition and subtraction?
2. How do you perform scalar multiplication of a matrix?
3. Can you explain matrix multiplication and when it's defined?
4. How can you compute the transpose of a matrix?
5. What are some common operations with matrices in linear algebra?

**Tip**: Always ensure that matrices have compatible dimensions for operations like addition and subtraction!

Given the following matrices, if possible, determine 3B - 3A. If not, state 'Not Possible'.

Learn how to determine if the matrix operation 3B - 3A is possible with given matrices A and B. Understand scalar multiplication and matrix subtraction for grades 10-12.

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