Math Problem Statement

Match the function with a grab and explain the identifying factors that led you to your deduction. The functions: y=2^x y= 3^-x y=-3^-x y=-0.5^-x y =2^-x -2 y= 1.5^x -2

Solution

To match the given functions with their corresponding graphs, let's analyze the behavior of each function. I'll outline key identifying factors for each:

1. y=2xy = 2^x

  • Identifying Factors:
    • Exponential growth function.
    • The graph passes through the point (0,1) since 20=12^0 = 1.
    • As xx increases, yy increases rapidly.
    • As xx decreases, the graph approaches the x-axis but never touches it (asymptotic to the x-axis).

2. y=3xy = 3^{-x}

  • Identifying Factors:
    • Exponential decay function.
    • Equivalent to y=13xy = \frac{1}{3^x}.
    • The graph passes through the point (0,1).
    • As xx increases, yy approaches 0.
    • As xx decreases, yy increases rapidly.

3. y=3xy = -3^{-x}

  • Identifying Factors:
    • Reflects the exponential decay function y=3xy = 3^{-x} across the x-axis.
    • The graph passes through the point (0,-1).
    • As xx increases, yy approaches 0 from below.
    • As xx decreases, yy decreases rapidly in the negative direction.

4. y=0.5xy = -0.5^{-x}

  • Identifying Factors:
    • This is also an exponential decay function, but with a negative sign.
    • Reflects y=0.5xy = 0.5^{-x} (which is equivalent to y=2xy = 2^x) across the x-axis.
    • The graph passes through the point (0,-1).
    • As xx increases, yy decreases rapidly in the negative direction.
    • As xx decreases, yy approaches 0 from below.

5. y=2x2y = 2^{-x} - 2

  • Identifying Factors:
    • Exponential decay function, shifted down by 2 units.
    • Equivalent to y=12x2y = \frac{1}{2^x} - 2.
    • The graph passes through the point (0, -1) (because 202=12=12^{-0} - 2 = 1 - 2 = -1).
    • As xx increases, yy approaches -2, but never touches it (asymptotic to y=2y = -2).

6. y=1.5x2y = 1.5^x - 2

  • Identifying Factors:
    • Exponential growth function, shifted down by 2 units.
    • The graph passes through the point (0,-1) (because 1.502=12=11.5^0 - 2 = 1 - 2 = -1).
    • As xx increases, yy increases but starts from -2.

Matching Process:

  1. Identify asymptotes: Graphs with horizontal asymptotes like y=2y = -2 correspond to shifted functions.
  2. Sign analysis: Positive growth or decay will have curves above the x-axis (unless shifted down).
  3. Exponential base comparison: The rate of increase/decrease helps to distinguish between bases like 2, 1.5, and 3.

Would you like to discuss these in relation to specific graphs or need further clarification?


Relative Questions:

  1. How does shifting a function vertically affect its graph?
  2. What is the impact of a negative exponent in exponential functions?
  3. How can the base of an exponential function change the steepness of the graph?
  4. Why does a function with a negative sign reflect over the x-axis?
  5. What role do asymptotes play in identifying exponential functions?

Tip: When analyzing functions, always start by considering their basic form before applying transformations like shifts, reflections, or scaling.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Graph Analysis
Transformations

Formulas

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Theorems

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Suitable Grade Level

Grades 10-12