To make \( x \) the subject of the equation \( y = -6 \times 10^{-5}x + 54.373 \), follow these steps:

1. Start with the equation:
   \[
   y = -6 \times 10^{-5}x + 54.373
   \]

2. Subtract 54.373 from both sides to isolate the term with \( x \) on one side:
   \[
   y - 54.373 = -6 \times 10^{-5}x
   \]

3. Divide both sides by \(-6 \times 10^{-5}\) to solve for \( x \):
   \[
   x = \frac{y - 54.373}{-6 \times 10^{-5}}
   \]

4. Simplify the equation if necessary. The final result is:
   \[
   x = \frac{54.373 - y}{6 \times 10^{-5}}
   \]

So, \( x \) as the subject of the equation is:
\[
x = \frac{54.373 - y}{6 \times 10^{-5}}
\]

Would you like details on any of these steps or have any other questions?

Here are five related questions you might find interesting:
1. How can we rearrange equations when dealing with logarithmic functions?
2. What is the impact of different signs on the rearrangement of equations?
3. How can we solve for \( x \) when the equation is quadratic?
4. What are some methods for simplifying complex algebraic expressions?
5. How can we solve equations involving exponents?

**Tip:** When rearranging equations, always perform the same operation on both sides to maintain the equality.

Learn how to rearrange the equation y = -6E-05x + 54.373 to solve for x. This problem involves isolating x in a linear equation, suitable for students in Grades 7-9.

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