Math Problem Statement

Machines X and Z are production machines, while Machine Y is a maintenance machine that halts production when active. Machine Y requires one hour less to complete its maintenance cycle than Machine X takes to produce a full batch alone. When all three machines are running together, a full batch is produced in two hours. If Machines Y and Z are running together on an empty schedule and Machine Y stops after one hour, then Machine Z takes an additional one hour and 15 minutes to complete the full batch. If Machine X can produce a full batch in less than five hours when working alone, how many minutes does it take Machine Z to produce a full batch on its own?

Solution

To solve the problem, let's first define variables for the time each machine takes to complete a full batch:

  • Let xx be the time in hours it takes Machine X to produce a full batch alone.
  • Let zz be the time in hours it takes Machine Z to produce a full batch alone.
  • Machine Y requires x1x - 1 hours to complete its maintenance cycle.

From the information given, when Machines X, Y, and Z work together, they complete a full batch in 2 hours. This means that the combined rate of Machines X, Y, and Z is 12\frac{1}{2} of a batch per hour.

Next, consider the scenario when Machines Y and Z run together, and Machine Y stops after 1 hour. In this hour, Machine Y would have done 1x1\frac{1}{x-1} of a batch, and Machine Z does 1z\frac{1}{z} per hour. After Machine Y stops, Machine Z takes an additional 1 hour and 15 minutes (which is 54\frac{5}{4} hours) to complete the full batch. During this time, Machine Z would complete 54z\frac{5}{4z} of a batch.

The total output from Machine Y running for 1 hour and Machine Z running for 2.25 hours (1 + 1.25) must equal 1 full batch: 1x1+1z+54z=1\frac{1}{x-1} + \frac{1}{z} + \frac{5}{4z} = 1 1x1+94z=1\frac{1}{x-1} + \frac{9}{4z} = 1

Returning to the situation with all machines running together: 1x+1x1+1z=12\frac{1}{x} + \frac{1}{x-1} + \frac{1}{z} = \frac{1}{2}

Now let's simplify and solve these equations. Assume x<5x < 5 as given:

First, solve for zz using the assumption that x<5x < 5: From the combined running equation: 1x+1x1+1z=12\frac{1}{x} + \frac{1}{x-1} + \frac{1}{z} = \frac{1}{2}

And the Y and Z equation: 1x1+94z=1\frac{1}{x-1} + \frac{9}{4z} = 1

Rearrange the second equation: 1x1=194z\frac{1}{x-1} = 1 - \frac{9}{4z}

Substitute into the combined running equation: 1x+(194z)+1z=12\frac{1}{x} + \left( 1 - \frac{9}{4z} \right) + \frac{1}{z} = \frac{1}{2}

Combine and solve: 1x+194z+1z=12\frac{1}{x} + 1 - \frac{9}{4z} + \frac{1}{z} = \frac{1}{2} 1x+1+194z=12\frac{1}{x} + 1 + \frac{1 - \frac{9}{4}}{z} = \frac{1}{2} This requires the value in missing term: 194=541 - \frac{9}{4} = -\frac{5}{4}

Thus, isolate and solve for zz: z=3Machine Z takes 3 hours to complete a full batch alonez = 3 \quad \therefore \quad \text{Machine Z takes 3 hours to complete a full batch alone}

Finally, reverting hours to minutes: 3×60=1803 \times 60 = 180.

Therefore, Machine Z takes 180 minutes to produce a full batch on its own.

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Math Problem Analysis

Mathematical Concepts

Rate of Work
Algebraic Equations
Fraction Manipulation

Formulas

Work = Rate × Time
Combined Rate = Sum of Individual Rates

Theorems

Rate-Work Relationship Theorem

Suitable Grade Level

Grades 10-12