Math Problem Statement

A can do a piece of work in 10 days and B in 20 days. Another friend C whose efficiency is twice of A joined them. All three started working together but C left 4 days before the completion and A left 3 days before the completion. In how many days work get completed?

Solution

To solve this problem, we need to calculate the total work and how much each person contributes. Let's break down the work:

Step 1: Determine the work rates

  • A's rate: A can complete the work in 10 days, so A's work rate is 110\frac{1}{10} of the work per day.
  • B's rate: B can complete the work in 20 days, so B's work rate is 120\frac{1}{20} of the work per day.
  • C's rate: C's efficiency is twice that of A. So, C can do the work in 102=5\frac{10}{2} = 5 days, which means C's work rate is 15\frac{1}{5} of the work per day.

Step 2: Calculate the combined work rates when all three are working together

When A, B, and C work together: Combined work rate=110+120+15\text{Combined work rate} = \frac{1}{10} + \frac{1}{20} + \frac{1}{5} Let's find the common denominator (which is 20): Combined work rate=220+120+420=720\text{Combined work rate} = \frac{2}{20} + \frac{1}{20} + \frac{4}{20} = \frac{7}{20} So, together they complete 720\frac{7}{20} of the work in one day.

Step 3: Work completed before C and A leave

Let the total time for the work completion be tt days. The events to consider:

  1. For the first t4t-4 days: All three are working together, so they complete (t4)×720(t-4) \times \frac{7}{20} of the work.
  2. For the next day t3t-3: Only A and B are working, so their combined work rate is 110+120=320\frac{1}{10} + \frac{1}{20} = \frac{3}{20}.

Step 4: Calculate total work done

The total work done is 1 (which is the whole work): 720(t4)+320=1\frac{7}{20}(t - 4) + \frac{3}{20} = 1

Step 5: Solve for tt

720t2820+320=1\frac{7}{20}t - \frac{28}{20} + \frac{3}{20} = 1 720t2520=1\frac{7}{20}t - \frac{25}{20} = 1 Multiply through by 20 to clear the fraction: 7t25=207t - 25 = 20 7t=457t = 45 t=4576.43 dayst = \frac{45}{7} \approx 6.43 \text{ days}

So, the work is completed in approximately 6.43 days.

Conclusion:

The total work is completed in about 6.43 days.

Would you like a detailed explanation of any step or further questions? Here are some related questions:

  1. How do we calculate work done when people leave at different times?
  2. What happens if C leaves earlier than 4 days before completion?
  3. How would the solution change if C's efficiency was different?
  4. What if B had left earlier instead of A?
  5. How to solve similar problems with varying work rates?

Tip: Always remember to break down complex problems into smaller, more manageable parts for easier analysis and solution.

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Math Problem Analysis

Mathematical Concepts

Rate of work
Combined work rates
Equations with fractions

Formulas

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Theorems

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Suitable Grade Level

High School