Math Problem Statement

Akan dibuat nomor-nomor undian yang terdiri atas satu huruf dan diikuti dua buah angka yang berbeda dan angka kedua adalah bilangan genap. Banyaknya nomor undian adalah...

Solution

The question asks about creating lottery numbers that consist of one letter followed by two different digits, with the second digit being even. The task is to calculate how many such lottery numbers can be created.

Let's break down the problem:

  1. First character (letter): There are 26 letters in the alphabet, so there are 26 possible choices for the first character.

  2. First digit: Any digit from 0 to 9 can be used, which gives us 10 possible choices for the first digit.

  3. Second digit (even number): The second digit must be an even number. The digits that are even are 0, 2, 4, 6, and 8, which means there are 5 possible choices for the second digit.

  4. Digits must be different: The first digit and second digit must be different, so if the first digit is even, there will be only 4 remaining choices for the second digit, but if the first digit is odd, all 5 choices are still valid.

Calculation:

  • For each of the 26 letters, there are 10 possible choices for the first digit.
  • For each odd first digit (5 odd digits), there are 5 choices for the second digit.
  • For each even first digit (5 even digits), there are 4 choices for the second digit.

Thus, the total number of possible lottery numbers can be calculated as:

26×(5×5+5×4)26 \times (5 \times 5 + 5 \times 4)

Let me calculate this for you.The total number of possible lottery numbers is 1170. Therefore, the correct answer is option C. 1170.

Would you like further clarification or details on this? Here are some related questions you might find interesting:

  1. How many combinations are there if the second digit must be odd instead of even?
  2. What if the digits are allowed to repeat, how would that affect the number of combinations?
  3. How many combinations are possible if only letters A–M are allowed?
  4. What if the lottery numbers consist of three digits instead of two?
  5. How many combinations would there be if no digits are allowed to start with zero?

Tip: When solving counting problems like this, always consider restrictions carefully and break down the problem step by step.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Permutations

Formulas

Total combinations = 26 x (5 x 5 + 5 x 4)

Theorems

Basic counting principle

Suitable Grade Level

Grades 9-12