Math Problem Statement

Magazine Sales Our new magazine initially sells 300 copies per month. Research indicates that a vigorous advertising campaign could increase sales by 20% each month if our market were unlimited. But research also indicates that magazine sales in our area are unlikely to exceed 1200 per month. Make a logistic model of projected magazine sales.

Solution

To model the magazine sales, we can use a logistic growth model. This model is suitable here because it allows for an initial growth rate that eventually levels off as the sales approach a maximum, or "carrying capacity," due to market limitations.

Setting Up the Logistic Model

The logistic growth model is typically given by:

S(t)=K1+KS0S0ertS(t) = \frac{K}{1 + \frac{K - S_0}{S_0} e^{-rt}}

where:

  • S(t)S(t) is the sales projection at time tt (in months),
  • KK is the carrying capacity (maximum possible sales),
  • S0S_0 is the initial sales,
  • rr is the growth rate,
  • tt is the time in months.

Given Information

  • Initial sales S0=300S_0 = 300 copies per month,
  • Carrying capacity K=1200K = 1200 copies per month,
  • Monthly growth rate without limitation: 20%20\%, which gives us r=0.20r = 0.20.

Building the Model

Substituting the known values:

S(t)=12001+1200300300e0.20tS(t) = \frac{1200}{1 + \frac{1200 - 300}{300} e^{-0.20t}}

Simplification of the Term Inside the Denominator

  1. Calculate the ratio 1200300300\frac{1200 - 300}{300}: 1200300300=900300=3\frac{1200 - 300}{300} = \frac{900}{300} = 3

  2. Substituting back, the model becomes: S(t)=12001+3e0.20tS(t) = \frac{1200}{1 + 3 e^{-0.20t}}

Final Logistic Model

The projected magazine sales after tt months is given by: S(t)=12001+3e0.20tS(t) = \frac{1200}{1 + 3 e^{-0.20t}}

This function models the growth of magazine sales, accounting for both the initial increase in sales due to advertising and the market saturation at 1200 copies.

Would you like a breakdown of the calculation steps or have any other questions?


  1. How does the logistic model behave as tt \to \infty?
  2. What would the model predict for sales after 6 months?
  3. How does changing the growth rate rr impact the logistic model?
  4. If the carrying capacity increased to 1500, how would the model change?
  5. What if the initial sales were only 200 copies?

Tip: Logistic models are often used in scenarios with growth limitations due to resource constraints or market saturation.

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Math Problem Analysis

Mathematical Concepts

Logistic Growth Model
Exponential Decay
Limits and Carrying Capacity

Formulas

Logistic Growth Model: S(t) = K / (1 + (K - S_0) / S_0 * e^(-rt))
Simplified Logistic Model for this problem: S(t) = 1200 / (1 + 3 * e^(-0.20t))

Theorems

Logistic Growth Theorem

Suitable Grade Level

Grades 10-12