Math Problem Statement

  1. (pvq)→r

2.~ (q^r)↔ (p^q)

Solution

Let's break down and analyze both of these logical expressions step by step.

Expression 1: (pq)r(p \lor q) \rightarrow r

This is a conditional statement where:

  • pp and qq are propositions.
  • \lor represents the logical OR.
  • \rightarrow represents implication.

Truth Table for (pq)r(p \lor q) \rightarrow r:

ppqqpqp \lor qrr(pq)r(p \lor q) \rightarrow r
TTTTT
TTTFF
TFTTT
TFTFF
FTTTT
FTTFF
FFFTT
FFFFT
  • (pq)(p \lor q) becomes true if either pp or qq is true, and the implication (pq)r(p \lor q) \rightarrow r is only false when (pq)(p \lor q) is true and rr is false.

Expression 2: ¬(qr)(pq)\neg (q \land r) \leftrightarrow (p \land q)

This is a biconditional statement where:

  • ¬\neg represents the negation (NOT).
  • \land represents logical AND.
  • \leftrightarrow represents equivalence (if and only if).

Truth Table for ¬(qr)(pq)\neg (q \land r) \leftrightarrow (p \land q):

ppqqrrqrq \land r¬(qr)\neg (q \land r)pqp \land q¬(qr)(pq)\neg (q \land r) \leftrightarrow (p \land q)
TTTTFTF
TTFFTTT
TFTFTFF
TFFFTFF
FTTTFFT
FTFFTFF
FFTFTFT
FFFFTFT

The biconditional \leftrightarrow is true when both sides of the statement are either both true or both false.


Summary:

  1. (pq)r(p \lor q) \rightarrow r is a conditional statement that is only false when pqp \lor q is true and rr is false.
  2. ¬(qr)(pq)\neg (q \land r) \leftrightarrow (p \land q) is a biconditional statement that compares the truth values of ¬(qr)\neg (q \land r) and (pq)(p \land q), and it is true when both sides have the same truth value.

Would you like to dive deeper into any part of this, or see some specific examples?

Follow-up Questions:

  1. What is the meaning of a biconditional statement?
  2. How can the implication \rightarrow be used in logical proofs?
  3. What are De Morgan's laws in logic?
  4. How does the truth table help in understanding logical equivalences?
  5. Can you give an example where these logical statements apply in real-world scenarios?

Tip: The biconditional operator \leftrightarrow can be thought of as "both sides must either be true or both false."

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Propositional Logic
Truth Tables
Logical Operators
Biconditional Statements
Implication

Formulas

(p ∨ q) → r
~(q ∧ r) ↔ (p ∧ q)

Theorems

De Morgan's Laws
Biconditional and Implication Rules

Suitable Grade Level

Grades 9-12 (Advanced Logic in High School Mathematics)