Math Problem Statement

If ^3log 2 = a and ^2log 7 = b, find the values of I. ^3log 7 and II. ^27log 49.

Solution

The problem you've provided is related to logarithms with non-standard bases, specifically with the bases written in subscript. Here's how we can solve the given questions:

Given Information:

  • 3log2=a^3\log 2 = a
  • 2log7=b^2\log 7 = b

You are asked to find:

  1. 3log7^3\log 7
  2. 27log49^{27}\log 49

Solution:

Part I: 3log7^3\log 7

To solve for 3log7^3\log 7, we'll use the change of base formula. The general change of base formula is:

clogd=logdlogc^{c}\log d = \frac{\log d}{\log c}

Using this, we need to express 3log7^3\log 7 in terms of aa and bb.

3log7=log7log3^3\log 7 = \frac{\log 7}{\log 3}

We are already given 2log7=b^2\log 7 = b, which means log27=b\log_2 7 = b, but this doesn’t immediately help us in finding 3log7^3\log 7. However, we might have to express this in terms of known logarithms or base conversions.

Part II: 27log49^{27}\log 49

For 27log49^{27}\log 49, first, recognize that 49 is 727^2, so we can simplify:

27log49=27log(72)=2×27log7^{27}\log 49 = ^{27}\log (7^2) = 2 \times ^{27}\log 7

Then, applying the change of base formula again:

27log7=log7log27^{27}\log 7 = \frac{\log 7}{\log 27}

Now, substituting this back:

27log49=2×log7log27^{27}\log 49 = 2 \times \frac{\log 7}{\log 27}

At this point, you would need the values of log7\log 7 and log27\log 27 to compute the exact result. Alternatively, express log27\log 27 in terms of smaller logarithms if additional information is given.


Would you like more detailed steps for the computations? Here are five related questions that can help expand your understanding:

  1. How does the change of base formula work in logarithms?
  2. How can logarithmic identities simplify complex logarithmic expressions?
  3. What are the properties of logarithms that deal with exponents, like log(xn)=nlogx\log (x^n) = n \log x?
  4. How can logarithms with non-standard bases be converted to simpler base-10 or base-e logarithms?
  5. Why is the change of base formula useful when working with different logarithmic bases?

Tip: When working with logarithms, the change of base formula is one of the most powerful tools, especially when you need to switch between uncommon logarithmic bases.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula

Formulas

Change of base formula: ^c\log d = \frac{\log d}{\log c}
Logarithmic exponent rule: ^{c}\log (x^n) = n\times ^{c}\log x

Theorems

Change of Base Theorem

Suitable Grade Level

Grades 9-12