The equation you provided is a linear equation:

$y = 5x - 3$

This equation represents a straight line in the form $y = mx + b$, where:

• $m$ is the slope of the line, which in this case is 5.
• $b$ is the y-intercept, which here is $-3$.

Key points:

• Slope (m): The line rises by 5 units for every 1 unit it moves to the right.
• Y-intercept (b): The point where the line crosses the y-axis is $(0, -3)$.

Would you like a graph or further details on how to analyze this line?

5 Relative Questions:

1. How do you find the x-intercept of this line?
2. What is the equation of a line parallel to this one?
3. How does the slope affect the steepness of the line?
4. What would happen to the graph if you changed the slope to 2?
5. How do you solve for $x$ when $y = 0$?

Tip: To find where the line crosses the x-axis, set $y = 0$ and solve for $x$.