The equation shown in the image is:

$y = 5x - 3$

This is a linear equation in slope-intercept form ($y = mx + b$), where:

• $m = 5$ is the slope of the line.
• $b = -3$ is the y-intercept, meaning the line crosses the y-axis at $(0, -3)$.

Properties of the Line

1. Slope ($m$): Indicates the steepness of the line. A slope of 5 means that for every unit increase in $x$, $y$ increases by 5 units.
2. Y-intercept ($b$): This is where the line crosses the y-axis, at $(0, -3)$.
3. Graph Behavior: The line rises from left to right because the slope is positive.

To Graph:

1. Plot the y-intercept ($0, -3$).
2. Use the slope to find another point. From $(0, -3)$, move up 5 units and right 1 unit to locate $(1, 2)$.
3. Draw a straight line through these points.

Would you like me to solve for specific values of $x$ or graph it further?

Related Questions:

1. How would the equation change if the slope were halved?
2. What are the $x$- and $y$-intercepts of this line?
3. How does the graph behave when the y-intercept ($b$) is changed to a positive value?
4. Can you calculate the point where this line intersects another line (e.g., $y = -2x + 4$)?
5. How would the equation change if it passed through the origin?

Tip: Always check the slope and y-intercept when analyzing a line—it helps determine the direction and starting point quickly!